3.12 A fiber is characterized by an intermodal dispersion of 40 ns/km. If the core refrac- tive index is n,-1.49, what is the cladding index n2? 3.12 A fiber is characterized by an intermodal di...

Question

Question

$3.12 A fiber is characterized by an intermodal dispersion of 40 ns/km. If the core refrac- tive index is n,-1.49, what is the$

Answer 1

Answer #1

We have

$Ln1 n1n2 Cn2$

given

$\Delta$ t = 40 ns

L = 1 km

n₁ = 1.49

10° × 1.49 (1.49 2) -, 3×108 × n2

By solving the above equation for n₂

$n_2=\frac{2.22}{120\times10^5}=1.85\times 10^{-7}$

Answer 2

Similar Homework Help Questions

Consider a 15 km long step-index fiber with n1= 1.53 and n2 = 1.50. What is...

Consider a 15 km long step-index fiber with n1= 1.53 and n2 = 1.50. What is the attenuation per kilometer in this fiber if an input power of 0.500 W results in the output power of 0.100 W ? Calculate the critical angle at the core-cladding interface and the NA (numerical aperture) for the fiber.
Consider a step index single mode fiber with a length of 100km. The core index being 1.46, and th...

Consider a step index single mode fiber with a length of 100km. The core index being 1.46, and the cladding index 1.45 and a loss of .20dB/km at a wavelength of 1550nm. The dispersion coeffcient of this fiber at 1550nm is D = 1.5. For a high speed data with .8nm spectral width what is the group velocity delay?
1. An optical fiber has a core diameter of 4 micro-meters and the cladding refractive index...

1. An optical fiber has a core diameter of 4 micro-meters and the cladding refractive index n-= 1.46. In order to have a single mode propagation wavelengths at 850nm and above what is the maximum core refractive index we should use?