Question

A 1.8 kg object oscillates at the end of a vertically hanging light spring once every 0.40 s .

Part A Write down the equation giving its position y (+ upward) as a function of time t. Assume the object started by being compressed 16 cm from the equilibrium position (where y = 0), and released. Note: the equilibrium position is defined here as that location of the mass at rest when it is freely hung from the spring, not the unstretched position of the spring with no mass. Write down the equation giving its position  ( upward) as a function of time . Assume the object started by being compressed 16  from the equilibrium position (where  = 0), and released. Note: the equilibrium position is defined here as that location of the mass at rest when it is freely hung from the spring, not the unstretched position of the spring with no mass. y(t)=(0.16m)⋅sin(2πt0.40s) y(t)=(0.16m)⋅cos(t0.40s) y(t)=(0.16m)⋅cos(2πt0.40s) y(t)=(0.16m)⋅cos((0.40s)⋅t) SubmitRequest Answer Part B How long will it take to get to the equilibrium position for the first time? Express your answer to two significant figures and include the appropriate units. t t = nothingnothing SubmitRequest Answer Part C What will be its maximum speed? Express your answer to two significant figures and include the appropriate units. vmax vmax = nothingnothing SubmitRequest Answer Part D What will be the object's maximum acceleration? Express your answer to two significant figures and include the appropriate units. amax amax = nothingnothing SubmitRequest Answer Part E Where will the object's maximum acceleration first be attained? Where will the object's maximum acceleration first be attained? release point equilibrium point

Answer 1

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