Question

Using MATLAB Please

Write a MATLAB function that takes coord natos of four points as inputs and returns the coord nates of ntersection of the line passing through ooints 1 and 2 and the line passing through points 3 and 4. For function name and inout arguments, use: P line_int(P1, P2, P3, P4) The function should be able to handle row or column vector entries. This function will use a sub-function called line_eq. This sub-function takes coordinates of two points as inputs and returns m and b such that y mxb represents the equation of the line passing through these points. For sub-function name and input arguments, use: [m, b] = line-eq(PA, PB) This function should be able to handle row or column vector entries. 2- Check your function to find the intersection of two lines: (P [1 30 Line 1: passing through points (-1,0) and (3,6) Line 2: passing through points (-2,6) and (7,-3) Note 1 (sub-function line oq): The oquation of tno inay- mx + b, which passes through point A Ka·y, and point B rs, yf, g given by: XB-XA Note 2 (Pimary function line inty: The coordinates of the intersection point of two linos ym+b and y m+ b2 ara givan by: -m1

Answer 1

Save below code except OUTPUT as line_int.m

function [P]=line_int(P1,P2,P3,P4)

PA=[P1(1) P2(1) P3(1) P4(1)];

PB=[P1(2) P2(2) P3(2) P4(2)];

[m,b]=line_eq(PA,PB);

P=inv([-m(1) 1;-m(2) 1])*b;

function [m,b]=line_eq(PA,PB)

m1=(PB(2)-PB(1))/(PA(2)-PA(1));

b1=(PB(1)-m1*PA(1));

m2=(PB(4)-PB(3))/(PA(4)-PA(3));

b2=(PB(3)-m2*PA(3));

m=[m1 m2];

b=[b1;b2];

end

end

OUTPUT----------------------------------------------------------------------------------------------

>> line_int([-1 0], [3 6], [-2 6], [7 -3])
ans =

   1.0000
   3.0000