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Consider recursive divide-and-conquer algorithms with the following descriptions. For each, determine the running time in Big

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Answer #1

`Hey,

Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries

T(n)=8*T(n/2)+theta(n^3)

We can say theta(n^3)=c*n^3

So,

T(n)=8*T(n/2)+c*n^3

So, by master theorem

log2(8)=3

So,

n^3=theta(n^3)

So, By master theorem

T(n)=theta(n^3*log(n))

Kindly revert for any queries

Thanks.

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Consider recursive divide-and-conquer algorithms with the following descriptions. For each, determine the running time in Big-Theta notation. If necessary, you may assume that the regularity conditio...
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