m1 = 28.0106
m2 = 28.0134
2*(r2-r1) = 0.48*10^-3 m ---(1)
r2 = m2*v/(B*q)
r1 = m1*v(B*q)
r2/r1 = m2/m1
r2 = r1*(m2/m1) = r1*(28.0134/28.0106)
r2 = r1*1.0001
so, r1 = 0.9999*r2
so, from equation 1,
2*(r2 - 0.9999*r2) = 0.48*10^-3
1.9999*10^-4*r2 = 0.48*10^-3
r2 = 0.48*10^-3/(1.9999*10^-4)
= 2.4 m
ConstantsPeriodic Table Part A A mass spectrometer is being used to monitor air pollutants. It is difficult, however, to separate molecules with nearly equal mass such as CO (28.0106 u) and N2 (28.01...
A mass spectrometer is being used to monitor air pollutants. It is difficult, however, to separate molecules with nearly equal mass such as CO (28.0106 u) and N2 (28.0134 u). Part A How large a radius of curvature must a spectrometer have if these two molecules are to be separated at the film or detectors by 0.76 mm ? Express your answer using two significant figures. ΑΣΦ