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Suppose we have developed new versions of a processor with the following characteristics: Version Voltage 1.5 V 1.2V Clock ra

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Answer #1

A) Dynamic power = capacitance x voltage2 x frequency

for version 1

let capacitance be C

Dynamic power0 = C x (1.5) ^ 2 x 2.4 = 5.4 C

FOr version 2

let capacitance be C1

Dynamic power1 = C1 x (1.2) ^ 2 x 3 = 4.32C1

We know that Dynamic power1 is 15 % less than Dynamic power0

so Dynamic power1 = 0.85 x Dynamic power0

    4.32C1 = 5.4 C

   C1 = 5.4 / 4.32 C = 1.25

B)

Let Capacitance of version 1 will be C1

let capacitance of version2 C2

we know C2 = 0.7 x C1

let Dynamic power of version 1 = Dp1

Dynamic power of version 2 = Dp2

Dp2 = 0.65xDp1

C2 x V22 x frequency = 0.65 x (C1 x V12 x frequency1)

0.7x C1 x V22 x 3 = 0.65 x C1 x 1.5 ^ 2 x 2.4

V2 = 1.29 volt

C)

According to amdahl's law

speedup achieved = (1 - fraction enchanced)fraction enchanced speedup enhance

fraction enhanced = 30 %

speedup enhanced = 2

speed up achieved = (1-0.30)+00 = 1.33

D)

According to amdahl's law

speedup achieved = (1 - fraction enchanced)fraction enchanced speedup enhance

fraction enhanced = 30 %

speedup required = 1.5

speedup enhanced = ?

1.5 .30 (1-0.30) + speedup enhanced

speed up enhanced = 4.5

so we need to improve the alu 4.5 times to get 1.5x system wide speedup

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Suppose we have developed new versions of a processor with the following characteristics: Version Voltage 1.5 V 1.2V Clock rate 2.4 GHz 3GHZ a) How much has the capacitive load varied between version...
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