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Can someone explain how they'd get the answer to this problem step-by-step?

4.7 Suppose a 32-bit instruction takes the following format: | OPCODE SR DR IMM . If there are 60 opcodes and 32 registers, w

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--> for 60 opcodes, 6 bits are needed.

--> 32 registers are there. So, 5 bits are needed for each SR and DR. total 10 bits.

--> remaining bits for IMM is 32 - 6 - 10 = 16

--> So, the range of values are -32768 to 32767 (-215 to 215-1 )

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Can someone explain how they'd get the answer to this problem step-by-step? 4.7 Suppose a 32-bit instruction takes the following format: | OPCODE SR DR IMM . If there are 60 opcodes and 32 regist...
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