Question

01:37:49 Question 2of 28 Step 1 of 4 A regression Analysis has been performed to estimate the model and the output is given. Regression Statistics 91092 82977 80140 23581 ultiple R justed R Square tandard Error bservations 8 ANOVA gnificance F 00165 df SS 24652 gression esidual otal 1,62635 0.05561 1,62635 33365 96000 -Upper 95% tStat 1430070 -5.40789 P-value 0.00001 00165 Lower 95% tandard Error 22648 13923 fficients 23882 0.75294 Ne Prev 68465 1.09362 9300 41226 ntercept iles Step 1 of 4: What is the intercept of the estimated regression equation? (Report to 2 decimal places.) m TablesKeypad Point Answer 3.24 © 2019 Hawkes Learning 01:37:37 of 28 Step 2 of 4 Question 2 A regression Analysis has been performed to estimate the model and the output is given. Regression Statistics ultiple R Square justed R Square tandard Error 91092 82977 80140 23581 ations ANOVA f SS Significance F .00165 MS 1,62635 0.05561 1.62635 33365 96000 24652 Total Ne Prev pper 95% 9300 Standard Error P-value 0.00001 p.00165-1.09362 Lower 95% 2.68465 Coefficients 3.23882 0.75294 tStat 14.30070 22648 13923 ntercept 5.40789 0.41226 Step 2 of 4: is there evidence of a linear relationship between credit card charges and miles traveled? (a 0.05) m TablesKeypad Answer 1 Point O No n Not enough data is provided to determine an answer OYes 0 2019 Hawkes Learning 01:37:25 Question 2of 28 Step 3 of 4 A regression Analysis has been performed to estimate the model and the output is given. Regression Statistics ultiple R Square 0.91092 82977 80140 23581 justed R Square tandard Error bservations ANOVA Significance F egression esidual otal 62635 33365 6000 9.24652 0.05561 Prev Coefficients 3.23882 0.75294 tandard Error 22648 P-value 00001 00165 Lower 95% 2.68465 Stat 14.30070 5.40789 pper 95% ntercept 3.79300 0.41226 step 3 of 4: Use the model to predict the credit card charges for a cardholder who traveled 1.5 thousand miles. Round to one decimal place. iles 3923 1.09362 m Tables Keypad Answer 1 Point Thousand Dollars 01:37:11 Question 2of 28 Step 4 of 4 uoservations ANOVA df SS Significance F 0.00165 MS 62635 05561 egression esidual otal 11.62635 9.24652 71.96000 pper 95% 79300 41226 over 95% Coefficients 3.23882 tandard Error 22648 Stat 4.30070 5.40789 ntercept 65 1.09362 00165 3923 75294 Step 4 of 4 Suppose a cardholder traveled 2 thousand miles. Find a 95% prediction interval for their credit card charges (in thousands of dollars). (Report to 2 decimal places) Ne Prev Tables Keypad Answer 1 Point Thousand Dollars Thousand Dollars Upper O 2019 Hawkkes Learning

Answer 1

step 1
intercept = 3.23882
= 3.24

step 2
p-value = 0.00165
p-value < alpha (0.05)

hence we reject the null hypothesis
we conclude that there is evidence of a linear relationship

option C) yes

step 3
y^ = 3.23882 - 0.75294 *x
= 3.23882 - 0.75294 * 1.5
= 2.10941
=2.1