pleas show all work May. 15, 2019 PROBLEMI (22%) Free body diagram: 24 K o (x,0) 0.5r No slip (a) An eccentric disk is rotating on the ground as shown in the figure above. The disk has radius r. T...
May. 15, 2019 PROBLEMI (22%) Free body diagram: 24 K o (x,0) 0.5r No slip (a) An eccentric disk is rotating on the ground as shown in the figure above. The disk has radius r. The distance between the center of mass of the disk (denoted as C) to its geometric center (denoted as O) sır. The angle of rotation of the disk is θ and the displacement at point O is x. The disk has mass m. The moment of inertia with respect to its center of mass is Jc- 2mr2, A spring force Kx is applied to point O. Follow the following procedure to derive the EOM of this dynamic system: (15%) Step 1 (elemental equations): (11%) (Easy) Euler equation of rotation around C: Newton's second law for translational motion at the center of mass C: Kinematic constraints: x.-x-. 0.5-r-sin θ 0.5 . r . cos θ 臭= Step 2 (eliminate the intermediate variables and derive the EOM in terms of e) (4%) (Hardi
May. 15, 2019 PROBLEMI (22%) Free body diagram: 24 K o (x,0) 0.5r No slip (a) An eccentric disk is rotating on the ground as shown in the figure above. The disk has radius r. The distance between the center of mass of the disk (denoted as C) to its geometric center (denoted as O) sır. The angle of rotation of the disk is θ and the displacement at point O is x. The disk has mass m. The moment of inertia with respect to its center of mass is Jc- 2mr2, A spring force Kx is applied to point O. Follow the following procedure to derive the EOM of this dynamic system: (15%) Step 1 (elemental equations): (11%) (Easy) Euler equation of rotation around C: Newton's second law for translational motion at the center of mass C: Kinematic constraints: x.-x-. 0.5-r-sin θ 0.5 . r . cos θ 臭= Step 2 (eliminate the intermediate variables and derive the EOM in terms of e) (4%) (Hardi