Question

4. The gas-phase dehydrogenation of propanol (A) to yield propionaldehyde (B) is in equilibrium at 230°C. Standard thermodynamic data for the reaction species at 298 K are: Propanol: Propionaldehyde : H.,--186 k/moi s'u-304.40 J/(mol K) Dihydrogen: H A -256 kJ/molSA 322.49 J/(mol K) Soc 130.68 J/(mol K) ) (4 points) Evaluate the standard enthalpy change of reaction (AH)at 298 K. ii (6 points Calculate the equilibrium constant at 298 K ) (8 points) Determine the equilibrium constant for this reaction at 230°C. State your assumption(s) v) (6 points) What is the ratio of propanol (A) to propionaldehyde (B) in a reactor at 1 bar containing 0.8 bar H2 and 0.1 bar He at 230°C? v) (6 points) If the goal is to maximize the propionaldehyde (B) yield, what conditions would you operate the reaction (i.e., temperature and pressure)? why?

Answer 1

Part 1 of the problem- Calculating $\Delta H_{rxn} , T =298 K$

Part II- Calculating Equilibrium Constant at 298 K, and Part III-Calculating equilibrium Constant at 230⁰C

34 Gen ternperotuke 230(2313 15) K 503-15 K Δητγκ,798K·e-prodets 29 sk ΔΗ.reoction. -w rod UC 3,293 K readerす298K) } dnce A, 208K ДН Scanned with amscanner

and Jiom see energy Constant Keat T 298K AS 322 49ok 三112-523 36 44 CamScanner

36 . 44 x1 3644 k3 e 36 eq 4,0967 지 0-7 An3 T. 2. 298 K =4.0 t 213 1 298K 2-503, IS Puttinq au those values , we w n K2 10000 1 S 314 S03 IS29 -3-188 1 -3-1881 2 n3 s cand 켜 k2: 0.04125 | A

Part IV- Calculating the ratio of propionaldehyde to the propanol

iv) ke have Kes at 230°c z o 04125. LV 230c can be aiven as 4-dihydro% lonaldeh eParhal pes urs 004125 O 04125 0, 05156 CH CH, CHO 0.05356 CH2CH2CH20h Scanned with CS

Part V- Maximizing the yield

End of the explanation.

As revi ou opionaldehyde the propanol ot current condihon, there is moe propan 어-than the-prop iona propionoJdehyde, h enCe o incVeasC th the e. SO crea Sei u e ncreasin suggest more yie ld o^ the yeochon LAß, jncreasing tem yeld mor e propionalcdehy Loilu y cs canned w