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Calculate the standard potential, Eº, for this reaction from its equilibrium constant at 298 K. X(s) + y2+(aq) = x2+(aq) + Y(

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Answer #1

Using, E°cell = 0.0592/n logK

Where, n = 2 (because two electrons are lost or gained)

K = 9.95×10^3

E°cell = 0.0592/2 ×log(9.95×10^3)

= 0.0592×3.99/2

= 0.118 V

> No idea why someone gave this a thumbs down, it worked for me!

crystal hammond Fri, Dec 3, 2021 5:49 PM

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Answer #2
if K=9.95×10³ n= 2 T=298 In K = nFE°/RT E°=In K×RT/nF = In (9.95×10³)×8.314×298/2×96500 = 0.118 V
source: Kat
answered by: katlego reneilwe
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