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Calculate the standard potential, E®, for this reaction from its equilibrium constant at 298 K. X(s)...
Calculate the standard potential, Eº, for this reaction from its equilibrium constant at 298 K. X(s) + y2+(aq) = x2+(aq) + Y(s) K = 9.95 103 E = V
Calculate the standard potential, Eº, for this reaction from its AGⓇ value. X(s) + y4+ (aq) — X4+ (aq) + Y(s) AGⓇ = 74.0 kJ E = V
Calculate the standard potential E°, for this reaction from its ΔG° value. X(s)+Y4+(aq)⟶X4+(aq)+Y(s)ΔG°=97.0 kJ
The equilibrium constant, K, for a redox reaction is related to the standard potential, E∘, by the equation lnK=nFE∘RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e−) , R (the gas constant) is equal to 8.314 J/(mol⋅K) , and T is the Kelvin temperature. Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.51×10−3.
The equilibrium constant, K. for a redox reaction is related to the standard potential, E, by the equation Fe(s) + Ni+ (aq) +Fe?+ (aq) + NI(s) FE In K = Express your answer numerically. View Available Hints) where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mole). R (the gas constant) is equal to 8.314 J/(mol-K). and T is the Kelvin temperature. ΟΙ ΑΣΦ h ? KK- Submit Previous Answers *...
The equilibrium constant, K, for a redox reaction is related to the standard potential, Eº, by the equation In K = nFE° RT where n is the number of moles of electrons transferred, F (the Faraday constant) is equal to 96,500 C/(mol e), R (the gas constant) is equal to 8.314 J/(mol · K), and T is the Kelvin temperature. Standard reduction potentials Reduction half-reaction E° (V) Ag+ (aq) + e +Ag(s) 0.80 Cu²+ (aq) + 2e + Cu(s) 0.34...
P6C.2 Calculate the value of A_G®(H,0,1) at 298 K from the standard potential of the cell Pt(s)[H2(g)|HCl(aq)|O2(g)|Pt(s), El = +1.23 V.
Calculate the standard cell potential (E∘) for the reaction X(s)+Y+(aq)→X+(aq)+Y(s) if K = 5.59×10−3
What is the equilibrium constant for the following reaction at 298 K? 2 Ag+(aq) + 2 I-(aq) → I2(s) + 2 Ag(s) Eº = +0.265 V Group of answer choices 2.99 x 104 1.60 x 107 9.04 x 108 87.9 7.73 x 103 Using data from the reduction potential table below and the reaction 2 Ag(s) + Pt2+(aq) → Pt(s) + 2 Ag+(aq) Eº = 0.38 V calculate the standard reduction potential of the half-reaction Pt2+(aq) + 2 e- →...
Calculate the standard cell potential (Eo) for the reaction X(s)Y (aq)X (aq)Y(s) if K 4.12x10-3 Express your answer to three significant figures and include the appropriate units. View Available Hint(s) HA ? Value Units Eo Previous Answers Submit If the equilibrium constant for a two-electron redox reaction at 298 K is 1.4x10-4, calculate the corresponding AG° and Ec under standard Express your answer using two significant figures. cel ΑΣφ conditions. ? AG0 = kJ Request Answer Submit Part B Express...