Question

Use SPSS for this exam, be sure to include all the following information to get full credits: (1) null and alternative hypoth

3. Use the data in the attached file (Final_Q3.sav) with 10 data points of Y and x1, X2, X3, X4, and X5 (a) Fit a simple line

Use SPSS for this exam, be sure to include all the following information to get full credits: (1) null and alternative hypotheses (15%) (2) nameofthe test(15%, explain why you chose it) (3) thetest statistic and its degree offreedom or ANOVAtable(if applicable) (30%! (4) p-value (15%), and (5) scientific conclusion (25%, using 0.05 significance). 1. Ostriches live in hot environments, and they are normally exposed to the sun for long periods Mammals in similar environments have special mechanisms for reducing the temperature of their brain relative to their body temperature. The mean body and brain temperature of six ostriches was recorded at typical hot conditions. The results, in degrees Celsius, showed in the following table (create your own data file) Ostrich Body temperature Brain temperature 38.51 39.32 2 38.45 39.21 38.27 39.20 3 38.52 4 38.68 38.62 5 39.09 38.84 6 38.18 (a) Test whether ostriches body temperature is equal to 38.5 degree Celsius. Report the 90% confidence interval for the mean body temperature. (10 pts) (b) Test whether any difference in temperature between body and brain for these ostriches. (Note: use ONE method you think the most appropriate and explain your answer.) (10 pts) 2. The following table lists total sales of a specific merchandise in six stores during four seasons (Final_Q2.sav) Sales (in thousand dollars) Fall Winter Summer Young Adults Young Adults Young Adults Young Adults 68 57 54 59 69 60 79 68 67 64 63 80 67 58 65 78 79 62 63 76 63 64 72 81 57 60 78 61 68 78 74 78 60 75 59 63 84 58 57 81 83 61 63 (a) Apply an appropriate analysis of variance to this data, justify your choice, and report the complete ANOVA table (must include Source, SS, DF, MS, F, and p). (10 pts) (b) Test the null hypothesis that the sales are the same for all seasons surveyed. (5 pts) (c) Assume that the winter is a control group. Use an appropriate test to compare the control mear sales with the other means, and conclude which season's sales is different from winter. (10 pts)
3. Use the data in the attached file (Final_Q3.sav) with 10 data points of Y and x1, X2, X3, X4, and X5 (a) Fit a simple linear model of Y on one independent variable X2 only, report (1) the Y intercept and regression coefficient; (2) test Ho: B 0. (10 pts) (b) Fit a full linear model of Y on ALL Xs, report (1) the Y intercept and partial regression coefficients; (2) test if there is a significant multiple regression relationship between Y and Xs; (3) test Ho: B3 0 (for X3). (15 pts) (c) Compare the two models in part (a) and (b), which one do you think fits the data better? Explain your answer. (5 pts) (d) Analyze and test whether the independent variables x2 and X4 significantly correlated. If the value of X2 increases, how would the value of X4 change? (10 pts) 4. The sex of consecutive children is independent in humans. For example, having had one boy already does not change the probability that the next child will also be a body. So the number of sons and daughters in families containing two children would match a binomial distribution with n 2, and p-0.51 (probability of having a boy). n! n-k In a data from the National Longitudinal Survey of Youth, which compiles data on the sex of children in a random sample of families of different sizes. The following table shows the number of sons in 2 two-child families. 440 Number of boys Observed number of families Expected number of families (binomial) 530 1330 580 2 2440 Total (a) Calculate the expected number of families containing exactly two children that have 0, or 1, or 2 boys using the binomial formula (round to the nearest tenth, i.e., one decimal point). (5 pts) (b) Test the null hypothesis that the number of boys in two-children families surveyed follow a binomial distribution. (10 pts)
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Answer #1

Answer:

1)

a)

蟋Untitled! [DataSetO]-IBM SPSS Statistics Data Editor File Edit View Data Iransform Analyze Direct Marketing Graphs Utlities

As shown in above image declare variable Body Temperature and Brain Temperature as Numeric with 2 decimal and Scale measure

Untitled1 DataSet0]- IBM SPSS Statistics Data Editor File Edit View Data Transform Anlye Direct Marketing Graphs Utilities Ad

包Untitled! [DataSetJ-BM SPSS Statistics Data Editor File Edit View Data Transform Analze Direct Marketing Graphs Utilities A

As shown above enter data in columns then check assumption of Normality using Non Parametric test

Output1 [Document1]- IBM SPSS Statistics Viewer File Edit View Data Transform Insert Format Analyze Direct Marketing Graphs U

As in above output p-value for both variable is > 0.05. Hence we can say that both variable Body and Brain Temperature are Nornally distributed

包.Untitledi DataSetO-IBM SPSS Statistics Data Editor File Edit View Data Transform Anlye Direct Marketing Graphs Utilities AdOne sample t test for Sample mean under hypothesis H0 : μ = 38.5V sH1 : μ 38.5

包Untitled! [DataSetJ-BM SPSS Statistics Data Editor File Edit View Data Transform Analze Direct Marketing Graphs Utilities AInput test value 38.5 and Run

Output! [Documenti 1-1BM SPSS Statistics Viewer File Edit View Data Transform Insert Format Analyze Direct Marketing GraphsAs shown above p-value for t test is 0.321 > 0.05. hence we fail to reject null hypothesis

i.e we can say that average body temperature is 38.5

Output1 [Document1]- IBM SPSS Statistics Viewer File Edit View Data Transform Insert Format Analyze Direct Marketing Graphs U

To obtain 90 % confidence interval perform one sample t test with test value 0. The 90 % confidence interval for Body temperature is (38.5407, 38.9410)

b)

包.Untitledi DataSetO-IBM SPSS Statistics Data Editor File Edit View Data Transform Analye Direct Marketing Graphs Utilities ATo perform Independent sample t test for hypothesis in b we have to enter data as shown above i.e Body and Brain temperature in single column and code Body part as 1 for Body and 2 for Brain

包.Untitledi DataSetO-IBM SPSS Statistics Data Editor File Edit View Data Transform Analye Direct Marketing Graphs Utilities Aand declare the Body part variable as Nominal and Enter value 1 for Body and 2 for Brain

包Untitled! [DataSetJ-BM SPSS Statistics Data Editor File Edit View Data Transform Analze Direct Marketing Graphs Utilities AAs shown above perform Independent sample t test to test hypothesis H0: d =0 Vs H1:d \neq 0

Output! [Documenti 1-1BM SPSS Statistics Viewer File Edit View Data Transform Insert Format Analyze Direct Marketing Graphs

The variances are equal as p-value for F test is 0.293 > 0.05.

So we look out for t test with equal variance assume

the p-value for t test is 0.000 < 0.05. Hence we can reject null hypothesis

i.e. There is significant difference in temperature between body and brain

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