1.
We need to first draw the graph. The draw the constraint lines with equality. Next, determine the feasible region.
Finally use the corner points on the objective function to determine the optimal corner point. That will be the solution.
The corner points are (0,0), (0,6), Crossing point of 2X1 + X2 = 6 and 6X1 + X2 = 12, and crossing point of 6X1 + X2 = 12 and X1 – X2 = 0
Now, crossing point between 2X1 + X2 = 6 and 6X1 + X2 = 12 is at (1.5, 3)
Crossing between 6X1 + X2 = 12 and X1 – X2 = 0 are at (1.71, 1.71)
The value of objective function at
(0,0) = 0
(0,6) = 5*0 + 6 = 6
(1.5,3) = 5*1.5 + 3 = 10.5
(1.71, 1.71) = 5*1.71 + 1.71 = 10.26
The optimal solution is (1.5, 3) and the objective function value is 10.5
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