please need assistance on part B of the question b) A planar manipulator has link lengths L1 2m and L2-1 m.Use the inverse kinematic equations to find the joint angles which will place the end poi...
b) A planar manipulator has link lengths L1 2m and L2-1 m.Use the inverse kinematic equations to find the joint angles which will place the end point at the following positions (x V2 i) Write the forward kinematic equations for the end point. [2 marks] ii) Calculate the link L2 joint angle iii) Calculate the link L1 joint angle [5 marks] [5 marks] [Q1 Total: 20 Marks] Question 2 a) Explain the principle of Reed switch sensors and give examples of two common applications [4 marks] b) The standard binary and gray codes are given in the Table Q2. Answer the following Table Q2 Standard binary and gray code 2 4 Decimal number Standard Binary code 000001 000 001 010 011 100 101 110 111 Gray code 011 010 110 111 101 100 i) Sketch a 3 bits absolute standard binary encoding disk and absolute gray encoding disk. Assume, the inner ring corresponds to bit 0, black sectors are "on" and white sectors are "off". Zero degree is on the right-hand side, with the
b) A planar manipulator has link lengths L1 2m and L2-1 m.Use the inverse kinematic equations to find the joint angles which will place the end point at the following positions (x V2 i) Write the forward kinematic equations for the end point. [2 marks] ii) Calculate the link L2 joint angle iii) Calculate the link L1 joint angle [5 marks] [5 marks] [Q1 Total: 20 Marks] Question 2 a) Explain the principle of Reed switch sensors and give examples of two common applications [4 marks] b) The standard binary and gray codes are given in the Table Q2. Answer the following Table Q2 Standard binary and gray code 2 4 Decimal number Standard Binary code 000001 000 001 010 011 100 101 110 111 Gray code 011 010 110 111 101 100 i) Sketch a 3 bits absolute standard binary encoding disk and absolute gray encoding disk. Assume, the inner ring corresponds to bit 0, black sectors are "on" and white sectors are "off". Zero degree is on the right-hand side, with the