It can be shown that for a linear harmonic oscillator the expectation value of the potential energy is equal to the expectation value of the kinetic energy, and the expectation values for r and p are clearly both zeros (0) Show that in the lowest energy state Ain agreement with the uncertainty principle (b) Confirm that for the higher states (Ax)(Ap) > h/2 .
It can be shown that for a linear harmonic oscillator the expectation value of the potential energy is equal to the expectation value of the kinetic energy, and the expectation values for r and p are...
For the simple harmonic oscillator ground state, because()0 and (p) 0 (expectation values of z and p are - Ar and Using this fact, you can estimate the ground state energy. Follow steps below for this calculation. a. For SHO potential V(z)--mw,2, write down the total energy of the ground state in terms of ΔΖ2 and p2. and constant parameters that characterize the SHO (m and w) total energy- Format Hint: Write(z*) as Δ2. not (Δε)2. The system considers two...
sider a simple harmonic oscillator with mass m and frequency ω The two lowest energy eigenstates have nd hu respectively. (a) (5 points) Calculate the expectation value of kinetic energy for the state with total energy Jhu. (b) (5 points) Calculate the expectation value of potential enerey for the state vith total enersy had
4. (20 points) Harmonic Oscillator The ground state wave function of a simple harmonic oscillator is (a) = Ae-42", where a = (a) Using the normalization condition, obtain the constant A. (b) Find (c), (), and Az, using the result of A obtained in (a). Again, A.= V(32) - (2) (c) Find (p) and Ap. For the latter, you need to evaluate (p). Hint: For a harmonic oscillator, the time-averaged kinetic energy is equal to the time-averaged potential energy, and...
For the ground state of a quantum harmonic oscillator, given by ?_0 = (?^(-1/2)*?^(-1/4))*?^(-(x^2)/(2?^2)) , show that the expectation values for potential and kinetic energy are equal.
A particle with mass m is in a one-dimensional simple harmonic oscillator potential. At time t = 0 it is described by the state where lo and l) are normalised energy eigenfunctions corresponding to energies E and Ey and b and c are real constants. (a) Find b and c so that (x) is as large as possible. b) Write down the wavefunction of this particle at a time t later c)Caleulate (x) for the particle at time t (d)...
A particle with mass m is in a one dimensional simple harmonic oscillator potential. At timet0 it is described by the superposition state where Vo, 1 and Vz are normalised energy eigenfunctions of the harmonic oscillator potential corresponding to energies Eo, E1 and E2 (a) Show that the wavefunction is normalised (b) If an observation of energy is made, what is the most likely value of energy and with what probability would it be obtained? (c) If the experiment is...
1. Consider a one-dimensional simple harmonic oscillator. We know that the total energy (E) has values: Here the angular frequency (o) corresponds to the freshman physics value of [spring constant/massja and (n) can be 0, 1,2, any non-negative integer. We know that the total energy is a measurable, observable quantity. The total energy includes the kinetic energy and the potential energy. Please explain whether or not the kinetic energy and the potential energy can both be measured at the same...
6. a) Calculate the expectation value of x as a function of time for an electron in a state that is a (normalized) equal mixture of the ground state and 1st excited state of a 1D HO b) Graph x vs time for the case k = 1 eV/nm2. What is its value at t=0? What is the period of the oscillation in femtoseconds? For the one-dimensional (1D) harmonic oscillator (HO) the potential energy function has the form V(a) k2/2,...
Recall that an energy eigenfunction of any central potential V (r) may be writtren as ψn`m(r, θ, φ) = Rn`(r)Y`m(θ, φ). This problem explores the behavior of ψ in the vicinity of the origin r = 0. Recall that the function u(r) = rRn`(r) satisfies the equation − ~ 2 2m d 2u dr2 + ~ 2 `(` + 1) 2mr2 + V (r) u = Eu, (1) where E is the energy eigenvalue. Note that Eq. (1) has the...
Answer 4 & 5 please! thank you! R values = Resistor value, R1 = 990 Ohms Resistor value, R2 = 2050 Ohms 4. Connect the 2nd resistor in parallel with the 1st resistor and connect that combination to the battery. Measure the following: The current passing through the R1, I1 = ___0.0058____ A The current passing through the R2, I2 = ___0.0031____ A The current supplied by the battery, I = ___0.0092____ A Calculate I1 + I2 =...