Question

Phosphorus-32 (P-32) is used in nuclear medicine as therapeutic agent in the treatment of several diseases. P-32 has a half life of 14.3 days and decays directly to its ground state by emitting a beta-minus particle. The decay table for P-32 is given. There are no excited energy states or other radiation emitted during this decay; therefore, P-32 is referred to as a "pure beta emitter.

A P-32 sample is prepared in the manufacturing site with an initial activity of 1MBq (10^6 transitions/sec). The sample is transferred to the hospital 4 days after. What will be the total energy released by P-32 sample at the hospital in 2 days?

Q2 Phosphorus-32 (P-32) is used in nuclear medicine as a therapeutic agent in the treatment of several diseases. P-32 has a half-life of 14.3 days and decays directly to its ground state by emitting a beta-minus particle. The decay table for P-32 is given. There are no excited energy states or other radiation emitted during this decay; therefore, P-32 is referred to as a "pure beta emitter." A P-32 sample is prepared in the manufacturing site with an initial activity of 1 MBq (106 transitions/sec). The sample Decay Data Table Mean Mean Energy Number per per Particle energRadiation Disintegration (Mev) Beta Minus 1.000 0.6948 is transfered to the hospital 4 days after. What will be the total energy released by P-32 sample at the hospital in 2 days?

Answer 1

32 4.3 43 七 dN

tu- nw.ne-of P-32 arovn 나t after 4 days N (4)- N (6,) Noe 一见 0004847