A)
Decay constant, lambda = ln(2)/14.3 = 4.85 x 10^-2 /days
Number of nuclei, N = (1.31 x 10^6)/(4.85 x 10^-2) = 2.34 x 10^12
Number of decays, dN = (2.34 x 10^12)[1 - e^(-4.85 x 10^-2 x 6.5)]
dN = 6.31 x 10^11 decays
B)
Energy, E = 6.31 x 10^11 x 700 x 1000 x 1.6 x 10^-19
E = 0.07 J
C)
Dose = (0.07/0.142)/10^-2 = 49.8 rad
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