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S16 = sigma Xi where (X1,X2 ... X16) iid geometric each with mean 2 Find mean of S16: Find standard deviation of S16: Find P(S16 > 40) using Central Limit Theorem, without correction factor: Find P...

S16 = sigma Xi where (X1,X2 ... X16) iid geometric each with mean 2

Find mean of S16:

Find standard deviation of S16:

Find P(S16 > 40) using Central Limit Theorem, without correction factor:

Find P(S16 > 40) using Central Limit Theorem, with correction factor:

Find p0 = exact = P(S16 > 40)

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Answer #1

We know mean ot geomatnc dietrbutiond)is L/p .4-P NB danotes neqative binomial clistibuion whe 2. Variance ot NB(y) : tandar

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S16 = sigma Xi where (X1,X2 ... X16) iid geometric each with mean 2 Find mean of S16: Find standard deviation of S16: Find P(S16 > 40) using Central Limit Theorem, without correction factor: Find P...
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