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5-73 Given the following data, use present worth analysis to find the best alternative, A, B, or C $10,000 15,000...
2. Given the following data, if the interest rate is 10%, use present worth analysis to...
2. Given the following data, if the interest rate is 10%, use present worth analysis to find the best alternative, A, B, or C. А в Initial cost, $ 10,000 15,000 12.000 Annual benefit. S 6,000 10,000 5.000 Salvage value, S 1,000 -2.000 3,000 Useful life, years 2
4. Using prese sing present worth analysis, choose the best alternative from the information below, assuming...
4. Using prese sing present worth analysis, choose the best alternative from the information below, assuming interest is 12%, and a 15 year useful life. Alternative Initial Cost Uniform Net Annual Benefit $75,000 $35,000 $55,000 Salvage Value $7,500 $ 6,000 $10,000 $20,000 $15,000 $40,000 NPWar NPWb= NPWC Best Alter 2. ཆར་བར་ དམ་ Solve for EUAW (A) i = 8% 1000 1500 2,000 2500
I wonder how can I sovle this problem fast. if you know any fast way pleas...
I wonder how can I sovle this problem fast. if you know any fast
way pleas show me. I know LCD of 2,3 and 4 is 12 for alternative A,
I have $10,000 which keep repeat and I need to write 5 times
P(P/F,i,n) for calculating present value of $10,000. this takes
long time. any suggesiton for solving this question faster.in exam,
I have access to table and calculator.
5-73 Given the following data, use present worth analysis to find...
Use Present Worth Analysis to determine whether Alternative A or B should be chosen. Items are...
Use Present Worth Analysis to determine whether Alternative A or B should be chosen. Items are identically replaced at the end of their useful lives. Assume an interest rate of 3% per year, compounded annually. Alternative A 340 60 Alternative B 870 182 Initial Cost Annual Benefit Salvage Value Useful Life (yrs) 78 106 Alternative A, because it costs $65.43 less than Alternative B, in terms of present worth Alternative B, because it costs $65.43 more than Alternative A, in...
Question 1 10 pts Use Present Worth Analysis to determine whether Alternative A or B should...
Question 1 10 pts Use Present Worth Analysis to determine whether Alternative A or B should be chosen. Items are identically replaced at the end of their useful lives. Assume an interest rate of 7% per year, compounded annually. Initial Cost Annual Benefit Alternative A 480 100 1100 Alternative B 1,310 260 |168 3 Salvage Value 116 Useful Life (yrs) O Alternative B, because it only incurs the initial cost once every three years instead of every two years O...
Given the following two alternatives, the present worth (PW) of E2 is closest to: Hint: Use...
Given the following two alternatives, the present worth (PW) of E2 is closest to: Hint: Use positive sign for cash outflow and negative sign for cash inflow. Alt. E1 Alt. E2 Capital Investment, $ 6,000 12,000 Annual Expenses, $ 150 175 Useful life, years Salvage value, $ none 4,000 Less than $10,000 Between $10,000 - $10,500 Between $10,500 - $11,000 O Greater than $11,000
Problem (2): Consider the following three mutually exclusive alternatives. MARR is 10%. Alternative 1 10,000 Alternative...
Problem (2): Consider the following three mutually exclusive alternatives. MARR is 10%. Alternative 1 10,000 Alternative 2 14,500 Alternative 3 20,000 $3,000 increasing by 500 each year thereafter negligible $5,000 Initial investment Annual yielded returns Salvage Value Service life $5,000 $5,000 negligible 6 a) Compute the payback (PB) period and discounted PB period of each alternative. Based on the PB period, which alternative do you recommend? b) Using Annual-worth analysis, which alternative do you recommend?
show me through an equation please. thank you. 3. Using present worth analysis, decide which of...
show me through an equation please. thank you.
3. Using present worth analysis, decide which of the two options shown below is the best at 6% annual interest. First cost O&M Annual benefits Overhaul at the end of year 4 Salvage value Useful life, in years Machine A $15,000 $600 $5,000 $0 $1,000 Machine B $20,000 $400 $5,200 $1,000 $2,000 4
Calculate the present worth of the Alternative "A". Assume the interest rate is 2% per year,...
Calculate the present worth of the Alternative "A". Assume the interest rate is 2% per year, compounded annually. Alternative A Initial cost $1,000,000 Annual maintenance cost $50,000 Overhaul cost every 4 years $200,000 Salvage value $400,000 Useful life 40 years
Question 1 The cash flows given in table below are for two different alternatives. MARR =10%...
Question 1 The cash flows given in table below are for two different alternatives. MARR =10% Data IN Initial Cost Annual Benefits Salvage Value Useful Life in years M $20,000 $6,000 $5,000 $80,000 $10,000 $20,000 a) Determine the annual worth of alternative M b) Determine the annual worth of alternative N
2. Given the following data, if the interest rate is 10%, use present worth analysis to find the best alternative, A, B, or C. А в Initial cost, $ 10,000 15,000 12.000 Annual benefit. S 6,000 10,000 5.000 Salvage value, S 1,000 -2.000 3,000 Useful life, years 2
4. Using prese sing present worth analysis, choose the best alternative from the information below, assuming interest is 12%, and a 15 year useful life. Alternative Initial Cost Uniform Net Annual Benefit $75,000 $35,000 $55,000 Salvage Value $7,500 $ 6,000 $10,000 $20,000 $15,000 $40,000 NPWar NPWb= NPWC Best Alter 2. ཆར་བར་ དམ་ Solve for EUAW (A) i = 8% 1000 1500 2,000 2500
I wonder how can I sovle this problem fast. if you know any fast
way pleas show me. I know LCD of 2,3 and 4 is 12 for alternative A,
I have $10,000 which keep repeat and I need to write 5 times
P(P/F,i,n) for calculating present value of $10,000. this takes
long time. any suggesiton for solving this question faster.in exam,
I have access to table and calculator.
5-73 Given the following data, use present worth analysis to find...
Use Present Worth Analysis to determine whether Alternative A or B should be chosen. Items are identically replaced at the end of their useful lives. Assume an interest rate of 3% per year, compounded annually. Alternative A 340 60 Alternative B 870 182 Initial Cost Annual Benefit Salvage Value Useful Life (yrs) 78 106 Alternative A, because it costs $65.43 less than Alternative B, in terms of present worth Alternative B, because it costs $65.43 more than Alternative A, in...
Question 1 10 pts Use Present Worth Analysis to determine whether Alternative A or B should be chosen. Items are identically replaced at the end of their useful lives. Assume an interest rate of 7% per year, compounded annually. Initial Cost Annual Benefit Alternative A 480 100 1100 Alternative B 1,310 260 |168 3 Salvage Value 116 Useful Life (yrs) O Alternative B, because it only incurs the initial cost once every three years instead of every two years O...
Given the following two alternatives, the present worth (PW) of E2 is closest to: Hint: Use positive sign for cash outflow and negative sign for cash inflow. Alt. E1 Alt. E2 Capital Investment, $ 6,000 12,000 Annual Expenses, $ 150 175 Useful life, years Salvage value, $ none 4,000 Less than $10,000 Between $10,000 - $10,500 Between $10,500 - $11,000 O Greater than $11,000
Problem (2): Consider the following three mutually exclusive alternatives. MARR is 10%. Alternative 1 10,000 Alternative 2 14,500 Alternative 3 20,000 $3,000 increasing by 500 each year thereafter negligible $5,000 Initial investment Annual yielded returns Salvage Value Service life $5,000 $5,000 negligible 6 a) Compute the payback (PB) period and discounted PB period of each alternative. Based on the PB period, which alternative do you recommend? b) Using Annual-worth analysis, which alternative do you recommend?
show me through an equation please. thank you.
3. Using present worth analysis, decide which of the two options shown below is the best at 6% annual interest. First cost O&M Annual benefits Overhaul at the end of year 4 Salvage value Useful life, in years Machine A $15,000 $600 $5,000 $0 $1,000 Machine B $20,000 $400 $5,200 $1,000 $2,000 4
Question 1 The cash flows given in table below are for two different alternatives. MARR =10% Data IN Initial Cost Annual Benefits Salvage Value Useful Life in years M $20,000 $6,000 $5,000 $80,000 $10,000 $20,000 a) Determine the annual worth of alternative M b) Determine the annual worth of alternative N
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