please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...

Question

Question

please show steps.
A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing 8.24 μg/mL and diluting the

science chemistry

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

According to the given data:

1.690/1.000 = 10 mL * X/(5 mL * 8.24 $\mu$ g/mL)

i.e. 1.69 = X mL/4.12 $\mu$ g

i.e. X = 6.9628 $\mu$ g/mL

Therefore, the value of X ~ 6.96 $\mu$ g/mL

Add a comment

Answer 2

Similar Homework Help Questions

Mn was used as an internal standard for measuring Fe by atomic absorption. A standard mixture...

Mn was used as an internal standard for measuring Fe by atomic absorption. A standard mixture containing 2.00 Hg/mL Mn and 2.50 Hg/mL Fe gave a quotient (Fe signal/Mn signal) 1.05/1.00. A solution was prepared by mixing 10.00 mL of unknown Fe solution with 10.00 mL of standard containing 8.24 ug/mL Mn, and diluting to 50.00 mL; the measured absorbance signal at the Fe wavelength was 0.197, and at the Mn wavelength the absorbance was 0.116. Calculate the molar concentration...
A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectiv...

A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectively, after separation by isocratic HPLC. A solution was prepared by mixing 8.76 mg of Compound Y with 5.00 mL of unknown containing just Compound X, and diluting to 10.00 mL. Peak areas of 5.96 cm- (Compound X) and 4.86 cm (Compound Y) were measured. Find the concentration of Compound X in the unknown.
An aqueous solution is prepared by mixing 240.0 mL of 1.700 M CoBr2 with 130.0 mL...

An aqueous solution is prepared by mixing 240.0 mL of 1.700 M CoBr2 with 130.0 mL of 2.400 M LiBr and then diluting the mixture to a final volume of 1.000 L. What is the molar concentration of bromide ions in the final solution? Assume both salts dissociate completely.

A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard....

A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard. The signal readings for these were 0.115 units and 0.321 units respectively. Sufficient internal standard was added to an unknown sample solution to make it contain 15.00 ppm internal standard. This solution gave readings for the analyte and internal standard of 0.266 and 0.275 units respectively. Determine the concentration of the analyte in the unknown sample.
Co(ll) was used as an internal standard to analyze a sample of Ti(IV) with atomic absorption spectroscopy (AAS). A standard mixture containing 1.90 g Co/mL and 1.53 /g Ti/mL measured by AAS produced...

Co(ll) was used as an internal standard to analyze a sample of Ti(IV) with atomic absorption spectroscopy (AAS). A standard mixture containing 1.90 g Co/mL and 1.53 /g Ti/mL measured by AAS produced a signal-to-signal ratio of 2.04 Ti: 1.00 Co A mixture was prepared by combining 4.50 mL of a Ti(IV) solution of unknown concentration with 3.50 mL of a 14.4 ug/mL solution of Co(l1). The absorbance of the mixture at the Ti(IV) wavelength was 0.100 and the absorbance...
5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas...

5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas of 3 473 and 10 222, respectively, in a chromatographic analysis. Then 1.00 mL of 8.47 mM S was added to 5.00 mL of unknown X, and the mixture was diluted to 10.0 mL This solution gave peak areas of 5 428 and 4 431 for X and S respectively (a) Calculate the response factor for the analyte (b) Find the concentration of S...

1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of...

1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of 0.100 M NaCl. Solution A is prepared by pipeting 10 mL of the stock solution into a 250-mL volumetric flask and diluting to volume. Solution B is prepared by pipeting 25 mL of solution A into a 100-mL volumetric flask and diluting to volume. Solution C is prepared by pipeting 20 mL of solution B into a 500-mL volumetric flask and diluting to volume....
show calculations please 3. A standard solution of Fe(II) [10.0 ppm) was prepared, the appropriate reagents...

show calculations please 3. A standard solution of Fe(II) [10.0 ppm) was prepared, the appropriate reagents were added, and a series of standard solutions were prepared and the transmittance of the solutions were read out as follows: Vol. of std solution (ml) Final vol. (mL) %T 0.00 100.0 100.0 5.00 100.0 77.7 25.00 100.0 30.2 50.00 100.0 10.4 (a) (3 pts) plot a calibration curve and find out the slope and y-intercept for the linearly related Absorbance with concentration. (b)...
A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard....

A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard. The signal readings for these were 0.115 units and 0.321 units respectively. Sufficient internal standard was added to an unknown sample solution to make it contain 15.00 ppm internal standard. This solution gave readings for the analyte and internal standard of 0.266 and 0.275 units respectively. Determine the concentration of the analyte in the unknown sample. Select one: O A. 1.71 ppm OB. None...

2. A solution was prepared by mixing 4.00mL of 2.00x 103M Fe(NO), and 3,00mL of 5.00 x 103 your a...

2. A solution was prepared by mixing 4.00mL of 2.00x 103M Fe(NO), and 3,00mL of 5.00 x 103 your average value of Ke to calculate the equilibrium concentration of FesCN2+ in the mixture. [Hint: Use as many significant figures as you legitimately can in your calculations] Kc 6.25E+01 5.42E+01 5.29E+01 5.98E-62 5.74E+01 2. A solution was prepared by mixing 4.00mL of 2.00x 103M Fe(NO), and 3,00mL of 5.00 x 103 your average value of Ke to calculate the equilibrium concentration...

please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...

Homework Answers

Add Answer to:
please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...

Post as a guest

Earn Coins

Mn was used as an internal standard for measuring Fe by atomic absorption. A standard mixture...

A known mixture of Compound X (1.52 mg/mL) and Compound Y (1.73 mg/mL) gave peak areas of 16.02 and 9.41 cm², respectiv...

An aqueous solution is prepared by mixing 240.0 mL of 1.700 M CoBr2 with 130.0 mL...

A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard....

Co(ll) was used as an internal standard to analyze a sample of Ti(IV) with atomic absorption spectroscopy (AAS). A standard mixture containing 1.90 g Co/mL and 1.53 /g Ti/mL measured by AAS produced...

5-29. A solution containing 3.47 mM X (analyte) and 1.72 mM S (standard) gave peak areas...

1. A series of dilute NaCl solutions are prepared starting with an initial stock solution of...

show calculations please 3. A standard solution of Fe(II) [10.0 ppm) was prepared, the appropriate reagents...

A standard sample was prepared containing 20.00 ppm of an analyte and 10.00 ppm internal standard....

2. A solution was prepared by mixing 4.00mL of 2.00x 103M Fe(NO), and 3,00mL of 5.00 x 103 your a...

please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...

Homework Answers

Add Answer to: please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...

Post as a guest

Earn Coins

Add Answer to:
please show steps. A solution was prepared by mixing 10.00 mL of unknown (X) with 5.00 mL of standard (S) containing...