Question

python

The Soundex Code code for surnames. It was code. All Al Soundex is a system that designed to produce one code for natha may be speled differenty, similar sounds. For example, Horn and Heron the same Soundex US Census Indexes from 1880 to the most recent availabie are caaloged by Soundex suname to Soundex convert your jning consonants with not by surname. To code, use the fierst letter of the and substitute the remaining consonants with the following chart BPFV 2. CSKGJQXZ 3, DT 5. MN 6. R Disregard the letters AEOUWYH ur surname has more codable letters, disregard them. If your surname Example 1: Partridge has the same code as Prater: P636. The d arnd g of Partridge are ignored. Example 2: Lee is code L000. There are no codable letters, so use zeroes to make the code 4 characters long If your surname has double letters, they should be treated as one letter. For example: Hammond. The second M should not be coded. For Lloyd, the second L should be not be coded. Other combinations of letters may be treated as one letter. If your surname hars two or more adjacent letters with the same coding number, treat the group as one letter For example: Fischer. S and C both have 2 for a coding number. You would not code the C, so the Soundex for Fischer would be the same as that of Fisher: F260.

Hi I have a project due on this Friday and I really can’t seem to figure this code out. If anyone could write this for me it’d be very appreciated. Thank you!

Answer 1

The required python code along with comments have been provided below:

def Soundex(surname):

   # Dictionary to story key:value pairs such that value is the
   # soundex code value of the key letter
   soundexDict = {}
   for letter in "BPFV":
       soundexDict[letter] = 1
   for letter in "CSKGJQXZ":
       soundexDict[letter] = 2
   for letter in "DT":
       soundexDict[letter] = 3
   for letter in "L":
       soundexDict[letter] = 4
   for letter in "MN":
       soundexDict[letter] = 5
   for letter in "R":
       soundexDict[letter] = 6

   # Final codename
   soundexCodename = ""
   # Converting everything to uppercase
   name = surname.upper()
   # Appending the first letter of the name to the codename
   soundexCodename += name[0]

   # List to store characters to be ignored
   ignoreCharacters = ['A','E','I','O','U','W','Y','H']

   # If the first letter was not in the ignored list
   if name[0] not in ignoreCharacters:
       # Store that the last adjacent letter's code number to prevent adding
       # an adjacent letter code with the same soundex code value
       lastAdjacentletterCode = soundexDict[name[0]]
   # Else, if the first letter was to be ignored
   else:
       # Simply store the last adjacent letter's code number as an invalid
       # soundex code value E.g = -1 or -2 or something
       lastAdjacentletterCode = -1

   # For every letter in the name after the first letter,
   for letter in name[1:]:

       # If the length of the codename has reached 4, then break out of
       # the for loop
       if len(soundexCodename) == 4:
           break
       # Else if the letter is not to be ignored
       elif letter not in ignoreCharacters:
           # If the last adjacent letter's soundex codenumber is not the same as
           # this letter code number,
           if soundexDict[letter] != lastAdjacentletterCode:
               # Append the letter to the codename
               soundexCodename += str(soundexDict[letter])
               # Update the last adjacent letter's code number to that of the
               # current letter
               lastAdjacentletterCode = soundexDict[letter]
       # Else if the letter was to be ignored, there is a break in adjacency, hence....
       else:
           # Make last adjacent letter's codenumber to some invalid value to show that
           # the adjacency is broken
           lastAdjacentletterCode = -1

   # After iterating through the name, if the soundexCode isn't 4 character long,
   if len(soundexCodename) < 4:
       # Format it to be appended upto length 4 with 0's
       soundexCodename = "{:0<4}".format(soundexCodename)

   # Return the code name
   return soundexCodename

if __name__ == "__main__":
   surname = raw_input("Enter surname: ")
   print("The soundex code is: "+Soundex(surname))

A screenshot is provided below for better understanding of the indentation etc.:

def Soundex(surname): # Dictionary to story key: value pairs such that value is the # soundex code value of the key letter soundexDict = {} for letter in "BPFV": soundexDict[letter] 1 for letter in "CSKGJQXZ" soundexdict[letter] = 2 for letter in "DT" soundexDict[letter]-3 for letter in "L soundexDict[letter] 4 for letter in "MN": soundexDict[letter] 5 for letter in "R" soundexDict[letter]6 # Final codename soundexCodename" # Converting everything to uppercase name Surname.upper () # Appending the first letter of the name to the codename soundexCodename += name[0] # List to store characters to be ignored ignoreCharacters I'A' , 'E' , ' l' ' ' 0' , 'U·'W' , ' Y' , 'H' ] # If the first letter was not in the ignored list if name [0] not in ignoreCharacters: # Store that the last adjacent letter's code number to prevent adding # an adjacent letter code with the same soundex code value lastAdjacentletterCode soundexDict[name[0]1 # Else, if the first letter was to be ignored else: # Simply store the last adjacent letter's code number as an invalid # soundex code value E.g--1 or -2 or something lastAdjacentletterCode -1 # For every letter in the name after the first letter, for letter in name [1:]: # If the length of the codename has reached 4, then break out of # the for loop


if len(soundexCodename) break 4: # Else if the letter is not to be ignored elif letter not in ignoreCharacters: # If the last adjacent letter's soundex codenumber is not the same as # this letter code number if soundexDict[letter] lastAdjacentletterCode: # Append the letter to the codename soundexCodename += ]) # Update the last adjacent letter's code number to that of the # current letter str(soundexDict[letter lastAdjacentletterCode soundexDict[letter] #Else if the letter was to be ignored, there is a break in adjacency, hence else: # Make last adjacent letter's codenumber to some invalid value to show that # the adjacency is broken lastAdjacentletterCode 1 # After iterating through the name, if the soundexcode isn't 4 character long, if len (soundexCodename) 4: # Format it to be appended upto length 4 with 0's soundexCodename":04".format (soundexCodename) # Return the code name return soundexCodename if_name main": surname raw_input ("Enter surname: ") print("The soundex code is: +Soundex (surname))

Sample Input/Output:

Enter surname: Hammond
The soundex code is: H553

Enter surname: Partridge
The soundex code is: P636

Enter surname: Prater
The soundex code is: P636

Enter surname: Fischer
The soundex code is: F260

Enter surname: Lee
The soundex code is: L000

Enter surname: Lloyd
The soundex code is: L300

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