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III. Standard Curves When we want to determine the concentration of an unknown solution, we typically measure a certain prope

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Answer #1
Standard Volume(ml) Mass(g) Density= mass/volume (g/ml) Concentration(M)

1

15 15.455 15.455/15=1.030 0.500

2

15 15.869 15.869/15=1.058 1.000

3

15 16.326 16.326/15=1.088 1.500

4

15 16.768 16.768/15=1.118 2.000

unknown

15 16.021 16.021/15=1.068 unknown

To get the calibration curve we are plotting the data in a graph. As told, density is independent variable so it is plotted along x axis. Concentration is dependent variable so it is plotted along y axis. First four points are plotted and the best fit line is drawn to get the calibration cure. Now to get the unknown concentration, we draw a density constant line from the x axis having density equal to that of unknown solution. Then we get an intersection point on the calibration curve. That point indicates the (density, concentration) coordinate of the unknown solution on the graph paper. So, drawing a peperendicular on the concentration axis from that point gives the corresponding concentration of the solution. Measuring the distance of the point on concentration axis from the orgin, we get the unknown concentration.

The whole thing I' ve uploaded as a graph. The x-axis grid unit is 0.001 and y-axis grid unit is 0.05. So, from the graph you can see, the red triangle on x axis is for unknown solution having density 1.068 g/ml , a line parallel to y axis(density constant line) from that cuts the calibration curve(black) and perpendicular from the intersection is cutting y axis to 1.15 M. So concetration of the unknown solution is 1.15 M.

Concentration(M) 2.5 density(g/ml) 09102 1020 4010 20931 : 11 1.1: 1.11 1.1 至13 114 E

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