Question

When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the toss on video, one of the cameras must be set up near the point where the toss will be made. When “action” is yelled out on the set, the initial separation between the drivers will be 200 m, the red car will accelerate from rest at a constant 6.12 m/s2, starting at xr = 0, and the green car will already be in motion with a constant speed of 60 km/h at xg = 200 m. How far from the initial position of the red car will the toss occur?

This is a more challenging problem with constant acceleration. Simply plugging numbers into an equation gets us nowhere, so sBut isnt this a dead end? With two unknowns in the equation, we cannot solve for either. However, lets use Eq. 2.4.2 againQuestion 1 What is the velocity of the green car, in meters per second and complete with sign? m/s VoQuestion 2 Substitute the known data into Eq. 2.4.2, for the green car and also the symbol tp and then finish this equation (

PLEASE ANSWER QUESTION 1 & 2. thanks.

This is a more challenging problem with constant acceleration. Simply plugging numbers into an equation gets us nowhere, so something extra is required. On a movie set, a red car and a green car are to move toward each other on opposite sides of a highway lane divider line, as indicated in the figure. reen x, carx ec car Example 2.4.4 Figure 1 When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the toss on video, one of the cameras must be set up near the point where the toss will be made. When "action" is yelled out on the set, the initial separation between the drivers will be 200 m, the red car will accelerate from rest at a constant 6.12 m/s2, starting at x 0, and the green car will already be in motion with a constant speed of 60 km/h at x2 -200 m. How far from the initial position of the red car will the toss occur?
But isn't this a dead end? With two unknowns in the equation, we cannot solve for either. However, let's use Eq. 2.4.2 again but this time for the green car, which has initial position xo 200 and constant speed of 60 kmh.
Question 1 What is the velocity of the green car, in meters per second and complete with sign? m/s Vo
Question 2 Substitute the known data into Eq. 2.4.2, for the green car and also the symbol tp and then finish this equation (in meters and seconds but don't show the units). What then is xp? Round all numbers to 3 significant digits. 2 Edit
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Answer #1

( ) 6O kmph GIven - velocity gan aan ,4° The - ais that the died ion ซู igus alco e oPPoste 60km Va hor-60 x60 sec 3600 se 36Thu timu dalende sud con Jo Jeach 81p ma daken Distance .taveljef 썽 quen can to seachYps 20-yP.. Since gran co vin Jraveincoi2 う t2-2Xp 6-12 t = 200-4p 16-667 Squasing puting valiaon Equaten (2002 400 y 6-12 过277.78g - 490. 7g1xp 40000 o Soluing thusQuestion 1. -16.667 m/s

Question 2. 103.206 m

If you have doubt in any of the step that i followed, feel free to ask.

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