9. Applying the Michaelis-Menten Equation I An enzyme catalyzes the reaction A = B. The enzyme is present at a con- cen...
13. An enzyme catalyzes the reaction A = B. The enzyme is present at a concentration of 2 nM, and the Vmax is 1.2 uMs. The K for substrate A is 10 uM. Calculate the initial velocity of the reaction, Vo, when the substrate concentration is (a) 2 uM, (b) 10 UM, (C) 30 UM.
Applying the Michaelis-Menten Equation II Another enzyme is found that catalyzes the reaction A <===> B Researchers find that the K for the substrate A is 4 uM, and the kcat is 20 min^-1 (a) In an experiment, [A] = 6 mM, and the initial velocity, Vo was 480 nM min^-1 What was the [Et] used in the experiment? (b) In another experiment, [Et] 0.5uM, and the measured Vo=5uM min^-1 What was the [A] used in the experiment? ( c)...
HUUR UUU UUILUUITUL LUIUILINU 2 PV, 10 pul, posta 10. Applying the Michaelis-Menten Equation II An en- zyme catalyzes the reaction M = N. The enzyme is present at a concentration of 1 nm, and the Vmax is 2 um s-1. The Kn for substrate M is 4 um. (a) Calculate kcat. (b) What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 2.0?
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
An enzyme catalyzes the reaction M↽−−⇀N . An enzyme catalyzes the reaction M = N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 1.9 uM -. The Km for substrate M is 2.9 uM. Calculate kcat kcat = 542.86 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.5? apparent Vmax = 0.526 UM s-1 apparent Km = 1.2
An enzyme that follows Michaelis-Menten kinetics has a initial velocity of 300 nM/s at a substrate concentration of 30 uM. The maximum velocity of 400 nM/sec. What is the Km for this enzyme in uM? (Give your answer as a number only. Type your response
An enzyme catalyzes the reaction M N. The enzyme is present at a concentration of 3.5 nM, and the Vmax is 2.9 PM s-. The Km for substrate M is 6.5 MM. Calculate kcat kcat = 1 What values of Vmax and Km would be observed in the presence of sufficient amounts of an uncompetitive inhibitor to generate an a' of 1.3? apparent Vmax = UM S-1 apparent Km = UM
What is the velocity of a Michaelis-Menten enzyme reaction (in terms of vmax) when the concentration of substrate is 4 times the value of KM? Show your work.
10. An enzyme catalyzes the reaction of Y to Z. The enzyme is present at a concentration of 1 nM. and the Vmax is 2 M/s. The Km for substrate Y is 4 M. Calculate kot