An enzyme that follows Michaelis-Menten kinetics has a initial velocity of 300 nM/s at a substrate...
Part A An enzyme that follows Michaelis-Menten kinetics has a KM value of 10.0 uM and a kcat value of 201 s-1. At an initial enzyme concentration of 0.0100 uM, the initial reaction velocity was found to be 1.07 x 10- uM/s. What was the initial concentration of the substrate, [S], used in the reaction ? Express your answer in micromolar to three significant figures. ► View Available Hint(s) PO ALO O O ? [S]; = MM UM
7. a) In an enzyme catalyzed reaction which follows the Michaelis-Menten kinetics. The substrate concentration (Km, Michaelis constant) needed to reach 50% of the maximum reaction velocity (Vmax) is 20 μΜ. What substrate concentration is required to obtain at least 75% of the maximum reaction velocity? Show the work to get full points. (5 points) b) You want to load 10 μg of protein in 15 μL into one of the 10% polyacrylamide gel well. The protein needs to be...
b. For an enzyme that displays Michaelis-Menten kinetics, what is the initial velocity as a function of Vmax when: a. [S] Km b. S] 0.1 Km c. [S] 50Km c. What will be the initial velocity (yo) for an enzyme that has Km 2.5 [S]? Your answer will be a fraction of Vmax a.
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...
please answer a,b and c. 4. Consider when enzyme E binds to Substrate Sassuming Michaelis-Menten kinetics kz[E]. [S] R= [S] + km a) What is the rate when [S] = km? b) What is the maximum rate (which is achieved when [S] >>> km) c) The rate of the reaction vs substrate concentration is given by the graph below. Indicate the VALUE of half of the maximum rate (Romex/2) and ku using the equations you derived in part a and...
9. Applying the Michaelis-Menten Equation I An enzyme catalyzes the reaction A = B. The enzyme is present at a con- centration of 2 nm, and the Vmax is 1.2 ums". The Km for substrate A is 10 um. Calculate the initial velocity of the reaction, Vo, when the substrate concentration is (a) 2 um, (b) 10 um, (C) 30 um.
c. 0.6 sec d. 1.67 sec 16. Which of the following about Michaelis-Menten enzyme kinetics is CORRECT? a. It assumes that the maximum reaction rate is proportional to the catalytic constant multiplied by the total enzyme concentration. b. It assumes that the enzyme-substrate complex concentration remains steady state. c. KM is defined as the substrate concentration at which the velocity of the reaction is maximal, so the unit is M. d. The KM is assigned to each enzyme regardless of...
For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity v (as a percentage of Vmax) ,observed at each of the following substrate concentrations. (Ex, v = xVmax, where x = an integer, fraction, or decimal number (two decimal places)) a) [S] = 0.1 Km _________ b) [S] = 2 Km _________ c) [S] = 10 Km _________
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
2) (5 marks) The enzyme Happyase follows simple Michaelis – Menten Kinetics a. The Km of Happyase for its substrate ICE is Km^s = 1mM. Happyase also acts on substrate CREAM and its Km^T =10mM. Is ICE or CREAM the preferred substrate for Happyase? Explain b. The rate constant k2 with substrate ICE is 2x10^4sec^ -1; with substrate CREAM, k2=4x10^5sec ^-1. Does Happyase use substrate ICE or substrate CREAM with greater catalytic efficiency? Show calculations and explain your answer