b)For the Michaelis-Menten kinetics
initial velocity as a function of Vmax is given by
v = Vmax[S]/Km+[S]
i) when [S] = Km , v= Vmax/2
ii) when [S] =0.1 Km
v= Vmax[S]/11[S] = Vmax/11
iii) [S] = 50 Km
Km = 0.02[[S] v= Vmax/1.02
c) Km = 2.5[S]
v = 0.2857 Vmax
b. For an enzyme that displays Michaelis-Menten kinetics, what is the initial velocity as a function of Vmax when: a. [...
For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity v (as a percentage of Vmax) ,observed at each of the following substrate concentrations. (Ex, v = xVmax, where x = an integer, fraction, or decimal number (two decimal places)) a) [S] = 0.1 Km _________ b) [S] = 2 Km _________ c) [S] = 10 Km _________
An enzyme that follows Michaelis-Menten kinetics has a initial velocity of 300 nM/s at a substrate concentration of 30 uM. The maximum velocity of 400 nM/sec. What is the Km for this enzyme in uM? (Give your answer as a number only. Type your response
What is the velocity of a Michaelis-Menten enzyme reaction (in terms of vmax) when the concentration of substrate is 4 times the value of KM? Show your work.
In the absence of allosteric effectors, the enzyme phosphofructokinase displays Michaelis–Menten kinetics (see Fig. 7.15). The v0/Vmax ratio is 0.9 when the concentration of the substrate, fructose-6-phosphate, is 0.10 mM. Calculate the KM for phosphofructokinase under these conditions (in units of mM).
The kinetics of enzyme catalyzed reactions can be described the Michaelis-Menten equation and the Eadie-Hofstee equation as shown below: V0 = (-Km) V0 / [S] + Vmax a). Please derive the Eadie-Hofstee equation starting from the Michaelis-Menten equation. b). The Vmax and Km of the enzyme catalyzed reaction can be derived from a plot of V0 versus V0/[S]. Please draw one of these plots and explain how do you use it to derive Vmax and Km. c). Please draw a...
A single-substrate enzyme that obeys Michaelis-Menten kinetics displays the following parameters: Kd = 3.1 x 10^-5 M; k1 = 107 M-1 s-1, and kcat = 10^4 s-1. Given this information, what is the value of the Michaelis constant Km? Express your answer in terms of mM to four significant figures.
Part A An enzyme that follows Michaelis-Menten kinetics has a KM value of 10.0 uM and a kcat value of 201 s-1. At an initial enzyme concentration of 0.0100 uM, the initial reaction velocity was found to be 1.07 x 10- uM/s. What was the initial concentration of the substrate, [S], used in the reaction ? Express your answer in micromolar to three significant figures. ► View Available Hint(s) PO ALO O O ? [S]; = MM UM
(I need help with part C, Drawing the expected Michaelis-Menten plot; Do NOT draw the Lineweaver-Burk plot. thanks!) 1. Michaelis-Menten kinetics- use the M-M equation to answer the following: a. An enzyme (5 µM) has a Vmax of 450 mM/min. What is kcat? b. When the substrate concentration is 50 mM, the initial velocity (V0) was measured to be 375 mM/min. Under the conditions described above, calculate the KM. c. Draw the expected Michaelis-Menten plot (label your axes and include...
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using the M-M equation that when [S] <<<Km, vo =[S][Et]kcat/Km. 2. What is Vmax? Provide both a mathematical and written description of Vmax? How can Vmax be experimentally altered? How can we use Vmax to determine the turnover number (kcat) of an enzyme-catalyzed reaction? What is the major challenge of determining Vmax from an Michaelis-Menten plot?