Question

(2 pts) Version A Spring 2019 A * 13. a) Write the enthalpy of formation equation for CsHs (gas). 30 +4412 ly Holio b) AG° at 298 K for the formation of C H gas from elements is -23.4 kJ/mol. Calculate the initial value of AG at 298 K for a reaction mixture that initially has... 4.00 grams carbon solid, 0.100 atm H gas, and 4.80 atm C He gas. Show work. 1. (5 pts) 4G= 46° + RT Ingen AL = -23.4 kJ/mol + 8.34 (298) en 4.4 AU = 3.65* 103 Qeq = (4.60) - (400.1)) aeg: 4,4 c) Identify if part (b) is at equilibrium or not; Circle your choice. If not, in which direction will the reaction proceed in order to reach equilibrium? (2 pts) Is it at equilibrium? YES or NO If not, which direction will it go? 14. a) Write the Kochemical reaction for Co(OH)2 (2 pts) K-5.92 x 10-15 5,92 x 10-15 = [co2+] [OH-] b) Write the Krchemical reaction for [Co(OH)). (2 pts) Kr=5.0 x 10° K4 = /[co ""] [OH-]] 2 - c) Solve for the equilibrium constant, K.q, for the given reaction and determine if produ or reactants are favored at equilibrium. (2 pts) Co(OH)(5) + 2 OH' (aq) [Co(OH))” (aq) 5.0x10 a Trollkeq ksp x hf 10.10 7 Keg: 2.96 x 10-5 the reactants are favored 65

Can someone please help with #13 and 14?? Thank you!!!

Answer 1

(6) formation of Chemical reaction for the (co (OH)] 2 is given by kg = 5x108 (aq) Caq) Cot2 + 404 - Co (OH) I The formation constant (kg) is given i [co +2] [OH-] 4 Ks = [[ Cocowa)-1) / & - or. Exioo - [ Co +2] [on-74 | [(co (OH)4] 2] - Reaction for equilibrium constant (kea): cotoH), (s) = Ca + leaks ksp=5.92X10 15 co (aq) + 4040 = (co (OH) ] 2 Kf = 5x100 (aa) 2 (aq) Addition COCOH, C5) + 204 con 2 [Co (OH)4] , keq = ksp xk keq = 5.92 X 10 -15 x 5x109 Keq = 29.6 X 100 keq = 2.96X10-5

Q-14 (9) solubility product constant (kop) : It is the equilibrium constant for a solid substance when it is dissolving in an aqueous solution. The more soluble a substance, higher the value of kop. For a reaction, a A - B B + cc (aq) (aq) (8) Note Ksb = [B]} [c] a A is not included in kop equation because its concentration do not change the expression. So, COCOH)₂ (8) - Co+2 +2040 (aq) caq) ksp= [Cot2] [ OH-]² given ks = 5.92X10-15 5.92X10-15 = [cot] [OH-] ² |