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bints Previous Answers Zumintro6 8.P.085. My Na the following table. moles of sample mass of sample 4.43 g C6H6 atoms in sample molecules in sample 3.41e22 10.0567 mol 223. 939 0.218 mol H20 1.31e23 mol 69 47.0 2.65 x 1022 molecules CO2 22777e23 g 1.29 mol HCI A h 9 ol | 4.04 x 1024 molecules H20 mol 99 5.95e21 0.317 g CH3OH 420.00989 Wer Practice Another Version Submit Assignment Save Assignment Progress -arch

Answer 1

In 4.43 g 6 Ho atons in Z-11-610Z ) sample = 3.4101022x1. x 12 ( 6 forc+ = 40.92 x 1022. = 4.0 92 x 1023 atoms x 1022 atoms sort) In 3.939 H o Sy.oge 23 atoms atoms in sample = 1.37023 = 1.31X1023 x 3 (2 forth) In (2 sort & - 1 for o = 3.93 1023 . 2.65 x102l modecules co2. moles of sample =0.043998 mal Ро• 0,40 м оf 2.65 x 1022 6.023X1023 grams of sample = 0.04 3998 × 44,01 (Mul (9 e 1.936351989 ~ 1.94 g ) atoms in sampel = 2.65 X/0??x3 = 7.9581022 atoms In 1.29 mol HCl, atoms in sample= 7.97X1023 r. X 2 = 15.54X1023 = 1.5548,oph a 1.55x1024 atoms In Youx 1029 molecules moles of sample 4.04 Xlory - = 6.70562 mol mass of sample = 6.70J62X 18.01528 atoms in samele -9.04xolo 10 x 3 6.023 xlors ~ 6-7lmol mot) ginol) 120.83965249 1219 = 12.12 X 1024 a - 1.212X1025 ~ 1.21Xiots atoms In 0.3179 CH₃OH atoms in sample = 5.95 810' 6( for c+ 4 for tt = 35.7 x 1021 atong I for o) ~ 3.57x1022 atoms