Question

нокти 4. One mole of H2S gas escapes from a container by effusion in 77 seconds. How long would it take one mole of NH3 gas to escape from the same container?

Answer 1

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Sop By Graham's law we get Rate of diffusion of a gas is inversely related root of its molar mass. → to the square (Rakel gas1 (Rate gas 2 a Mgasa VM gas 1 = Time gas 2 Time gas 1 gas 1 : H₂S : Time = 11 q second Molar mass of gas 1= 32+2 = 34g (mol qas-2 NH3 I ; Time gay2 = let it be ta molar mass of gas 2 = 17 gimol foom is , we get from n we get To Me - TVM 77 V 34 * T2 = 77 second second 12 Time taken from the same to escape one container - mole of NH3 gas I sound = 54.45 second

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