Question

A gas effusion cellis loaded with O2 gas at STP it take 344 seconds 0.010% of the gas to effuse through the hole. Under the same conditions, an unknown gas takes 46 3 seconds for 0.010% of gas to offuse through the hole. Based on these data, what is the molar mass of the unknown gas in gimoll?

Answer 1

molar mass of unknown gas = 58.0 g/mol

Explanation

According to Graham's effusion law

t₂ / t₁ = (M₂ / M₁)^1/2

where t₁ = 34.4 s

M₁ = molar mass O₂ = 32.0 g/mol

t₂ = 46.3 s

Substituting the values,

46.3 / 34.4 = (M₂ / 32.0 g/mol)^1/2

(M₂ / 32.0 g/mol)^1/2 = 1.346

M₂ / 32.0 g/mol = (1.346)²

M₂ / 32.0 g/mol = 1.81

M₂ = (1.81) * (32.0 g/mol)

M₂ = 58.0 g/mol