How many moles of Ag ions are present in 10 ml of a 0.75 MAgNO, solution? Select one: O a. 0.91 x 10 O b. 2.0x 10 O...

Question

Question

Answer 1

Answer #1

mole of AgNO3 = volume of solution in L * molarity = 0.010 L * 0.75 mole / L = 7.50 * 10^-3 mole.

AgNO3 .................> Ag+ + NO3-

one mole AgNO3 produce one mole Ag+ ion.

so

mole of Ag+ = 7.50 * 10^-3 mole = 0.75 * 10^-2 mole.

option (d) is the answer.

Answer 2

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