Question

22) How many moles of CH3CH2Cl are contained in 548 mL of 0.0788 M CH3CH2Cl solution? A) 4.32 x 10-2 mol B) 2.32 x 10-2 mol C) 6.95 x 10-2 mol D) 1.44 x 10-2 mol E) 5.26 x 10-2 mol 23) How many milliliters of a 0.266 M CSNO3 solution are required to make 150.0 mL of 0.075 M CSNO3 solution? A) 53.2 ml B) 42.3 mL C) 18.8 ml D) 23.6 mL E) 35.1 ml 24) What is the concentration of magnesium ions in a 0.125 M Mg SOA solution? A) 0.125 M B) 0.0625 M C) 0.375 M D) 0.250 M E) 0.160 M 25) What is the concentration of sodium ions in a 1.225 M Na2SO4 solution? 26) What is the concentration of FeCl3 in a solution prepared by dissolving 30.0 g of FeCl3 in enough water to make 275 mL of solution? A) 6.73 x 10-4 M B) 0.673 M C) 1.49 M D) 1.49 % 103 M

Answer 1

Men x 1000 Veme) 0.0788 = n x1000 548 n=0.0788x548 1000 (n=0.043 moles] =14-32x16?mole MiVI = M2 V2 0-075x150 = 0.266X V2 0.266 V2 = 11:25 [V2=42:293 m/~ 42-3 me]