Moles = molarity × volume
= 2.4×.1
=.24
Na2SO4 (s) → 2 Na+1 (aq) + SO4-2
Total moles of ions = moles × no of molecules
=3×.24
= .72
Option C is CORRECT
How many total moles of ions are contained in 100.0 mL of a 2.4 M Na2SO4...
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