Question 4 Use the method of Laplace transform to find the solution of the initial value problem Zy" + y' + 4-2...
(1 point) Use the Laplace transform to solve the following initial value problem: y! -8y + 20y = 0 y(O) = 0, y (0) = 2 First, using Y for the Laplace transform of y(t), i.e., Y = {y(0), find the equation you get by taking the Laplace transform of the differential equation 2/(s(2)-8s+20) =0 Now solve for Y(s) = 1/[(9-4) (2)+(2)^(2)) By completing the square in the denominator and inverting the transform, find y() = (4t)sint
Find the Laplace transform Y(s) = L{y} of the solution of the given initial value problem: 1, y' + 9 = 0<t<T 0,7 <t< y(0) = 5, y'(0) = 4
Use the Laplace transform to solve the given initial-value problem. y" + 4y' + 29y = δ(t-a) + δ(t-3x), y(0) = 1, y"(0) = 0 y(t) = Need Help? Read ItTalik to a Tutor Use the Laplace transform to solve the given initial-value problem. y" + 4y' + 29y = δ(t-a) + δ(t-3x), y(0) = 1, y"(0) = 0 y(t) = Need Help? Read ItTalik to a Tutor
Find the Laplace transform y(s) of the solution of the given initial value problem. Then invert to find y(t). Write uc for the Heaviside function that turns on at c. not uc(t). S1, y" + 4y = ost< 2, y(0) = 6, 7(0) = 8 lo, 2 St<00; Y(s) = y(t) =
Use the Laplace transform to solve the following initial value problem: y" + 4y = f(t), y(0) = 0, y'(0) = 1 where f(t) = { if 0 <t <a sint if a <t< oo
[15] 9. By using the Laplace transform method solve the initial value problem Y" + 2y + y = sint, y(0) = 0, y(0) = 0.
o use Laplace Transform method to solve Initial Value Problem y" - 8y' & 1by = t² est y (8) = 1 y(0)=4
(4 points) Use the Laplace transform to solve the following initial value problem: y" – 2y + 5y = 0 y(0) = 0, y'(0) = 8 First, using Y for the Laplace transform of y(t), i.e., Y = L{y(t)}| find the equation you get by taking the Laplace transform of the differential equation = 01 Now solve for Y(3) By completing the square in the denominator and inverting the transform, find g(t) =
(6 points) Use the Laplace transform to solve the following initial value problem: y" – 10y' + 40y = 0 y(0) = 4, y'(0) = -5 First, using Y for the Laplace transform of y(t), i.e., Y = L{y(t)}, find the equation you get by taking the Laplace transform of the differential equation = 0 Now solve for Y(s) By completing the square in the denominator and inverting the transform, find y(t) =
QUESTION 3 Use Laplace Transform to solve the initial value problem y" + 9y = f(t) ,y(0) = 1, y'(0) = 3 where 6, f(t) 0 <t<nt i < t < 0