Question

Question 4 of 5 > The generic metal A forms an insoluble salt AB(s) and a complex ACs(aq). The equilibrium concentrations in a solution of ACs were found to be [A] = 0.100 M, [C] = 0.0170 M, and [ACs) = 0.100 M. Determine the formation constant, K. of ACs. The solubility of AB(s) in a 1.000 M solution of (aq) is found to be 0.153 M. What is the ke of AB? Ке

Answer 1

Dear student

Answer: The equlibrium equation for the formation of ACG complex is given by. A+ C = ACS formation constant for this reaction is ginen by kg = [AC] [A1 [c] [AC ] = 0.100M [AT = 0.100M [c ] = 0.0170M, putting these values in ean o , we get kg = 0.100M 0.160mx (0.0170M)S

(17810315 038 Mar - La Strots mos = 10's MS M 1419852 = 7.043x107x 1015 ms = 7.043 8108 M-5

• for solubility product kop. ACG Can) & Blag) + 56(a) A BIS) 0.153 - 0.153 o Initial • Change al equlibh 0.153. - 5X(0.153) 0.235 0.153 0.153 0.153 i Ksp = [AC slags] [Bead) [ABE)] [ Ecant = 0.153 x 0.153 = {.. [ABS] =18 0.153 X 0.153 (0.23575 2.3418162 7. 167 x 10-4 = 0.3266x10² = 32.66

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