Question

6. Which of the four carbocations shown is the most stable (will not rearrange) and which one(s) will undergo carbocation rearrangement(s)? Indicate the correct structures of the products of the carbocation rearrangements. To practice for the exam: use resonance structures to explain why you selected specific a carbocation as the most stable. Where applicable, use the curved arrow(s) to clearly draw the mechanism of the carbocation rearrangement. HO UW A. carbocation B is most stable and will not rearrange, and the products of rearrangements are OH om но в from A B. carbocation B is most stable and will not rearrange, and the products of rearrangements are HO ol он from A from C C. carbocation A is most stable and will not rearrange, and the products of rearrangements are from B from from D D. carbocation A is most stable and will not rearrange, and the products of rearrangements are но T ) OH X from from E. carbocation B rearrangements are is most stable and will not rearrange, and the products of

Answer 1

Carbocation B is most stable because of the back bonding of OH adjacent to it

rest rearrangement follows as

HOS stabilized by backbonding c. HC 1,2 Me shift HO To listen to y ou stabilized by backbonding 1,2 Hydride shift stabilized by resonance

HENCE CORRECT OPTION IS B

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