(1 point) Consider the initial value problem d'y dy dt2 dt dt Write down the Laplace transform of the left-hand sid...
1 point) Consider the initial value problem dy 29y--9e cos( dt dt2 dt Write down the Laplace transform of the left-hand side of the equation given the initial conditions Y(sA2-10s+29)+3s-24 Your answer should be a function of s and Y with Y denoting the Laplace transform of the solution y. Write down the Laplace transform of the right-hand side of the equation -9(s-5(S-5)A2+9) Your answer should be a function of s only. Next equate your last two answers and solve...
(1 point) Consider the initial value problem d2y dy 8 +41y8 cos(2t), dt dy (0) y(0) = -2 -6 dt dt2 Write down the Laplace transform of the left-hand side of the equation given the initial conditions (sA2-8s+41)Y+2s-18 Your answer should be a function of s and Y with Y denoting the Laplace transform of the solution y. Write down the Laplace transform of the right-hand side of the equation (-8s+32)/(sA2-8s+20) Your answer should be a function of s only...
(1 point) Consider the initial value problem a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of v(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). help (formulas) (sh2+4)Y(s)-(8s+5) Solve your equation for Y(s) b. c. Take the inverse Laplace transform of both sides of the previous equation to solve for...
(1 point) Consider the initial value problem where g)-t ifosi«5 a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). help (formulas) b. Solve your equation for Y(s) (s) = L {y(t)) = c. Take the inverse Laplace transform of both sides...
Consider the following initial value problem. y′ + 5y = { 0 t ≤ 1 10 1 ≤ t < 6 0 6 ≤ t < ∞ y(0) = 4 (a) Find the Laplace transform of the right hand side of the above differential equation. (b) Let y(t) denote the solution to the above differential equation, and let Y((s) denote the Laplace transform of y(t). Find Y(s). (c) By taking the inverse Laplace transform of your answer to (b), the...
1 point) Consider the initial value problem y" + 36y-cos(61), y(0)-6 (0)-8, a. Take the Laplace transform of both sides of the given differential equation to create the corresponding algebraic equation. Denote the Laplace transform of y(t) by Y(s). Do not move any terms from one side of the equation to the other (until you get to part (b) below). help (formulas) b. Solv e your equation for Y (s) Y(s) = L { y(t)) = c. Take the inverse...
(1 point) Find the solution to initial value problem dạy dt2 dy 169 + 64y = 0, y(0) dt = 10, y'(0) = 4 The solution is
(1 point) Use the Laplace transform to solve the following initial value problem: y" + 6y' - 16y = 0 y(0) = 3, y(0) = 1 First, using Y for the Laplace transform of y(t), i.e., Y = C{y(t)). find the equation you get by taking the Laplace transform of the differential equation = 0 Now solve for Y(s) = and write the above answer in its partial fraction decomposition, Y(S) = Y(s) = A. where a <b Now by...
1 point) Use the Laplace transform to solve the following initial value problem: y" - 9y' + 18y-0, y(0) -3, y' (0) 3 (1) First, using Y for the Laplace transform of y(t), i.e., Y-C00), find the equation you get by taking the Laplace transform of the differential equation to obtain (2) Next solve for Y (3) Now write the above answer in its partial fraction form, Y- (NOTE: the order that you enter your answers matter so you must...
(1 point) Use the Laplace transform to solve the following initial value problem: y" + 3y = 0 y(0) = -1, y(0) = 7 First, using Y for the Laplace transform of y(t), i.e.. Y = C{y(t)} find the equation you get by taking the Laplace transform of the differential equation = 0 Now solve for Y (8) and write the above answer in its partial fraction decomposition, Y(s) Y(8) = B b where a <b sta !! Now by...