Question

Find the sum of the first 23 to the n (23 exponent n) multiples of 23 for a given n using PYTHON. The value of n will not be small. Example (n = 12 ⇒ 5522883785959772985105087173078663)

Answer 1

_Python CODE ::

Multiples.py int(input ("Enter the n vaLue : ")) # Taking Input for n for i in range(1,24): # iterating loop for 23 values print ("(0) x {1:2) {2)".format ( n, i ,n.1)) # print ingl n 3 4

Output ::__

File Edit View Search Terminal Help aj@dlr3wolf:/tmp/Q$ ls Multiples.py aj@dlr3wolf:/tmp/os python3 Multiples.py Enter the n value 10024 10024 x 1 10024 10024 x 220048 10024 x 3 30072 10024 x 4 40096 10024 x 5=50129 10024 x 6=60144 10024 x 7=70168 10024 x 8=80192 10024 x 9=90216 10024 x 10 = 100240 10024 x 11 110264 10024 x 12 120288 10024 x 13 130312 10024 x 14 = 140336 10024 x 15 150360 10024 x 16 = 160384 10024 x 17 170408 10024 x 18 180432 10024 x 19 = 190456 10024 x 20200480 10024 x 21 = 210504 10024 x 22 220528 10024 x 23 230552 aj@dlr3wolf:/tmp/Q$

RAW PYTHON CODE ::...............

________________________________ Multiples.py ______________________________________

n = int(input("Enter the n value : ")) # Taking Input for n
for i in range(1,24): # Iterating loop for 23 values
   print("{0} x {1:2} = {2}".format(n,i,n*i)) # printing
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