An electron has an uncertainty in its position of 609 pm
What is the uncertainty in its velocity?
***Express your answer with the appropriate units.**
use Heisenberg uncertainty principle,
Δx*Δv = h/(4*pi*m)
Here:
Δv = 709 pm = 609*10^-12 m = 6.09*10^-10 m
mass, m = 9.11*10^-31 Kg
Putting values,
6.09*10^-10*Δ v = (6.626*10^-34)/(4*3.14*9.11E-31)
6.09*10^-10*Δ v = 5.791*10^-5
Δv = 9.509*10^4 m/s
Answer: 9.51*10^4 m/s
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