In research on the synthesis of superconductors, the following reaction is studied. What amount (in moles) of BaO is needed to react with 5.0g of CaO?
Tl2O3(l) + 2 BaO(s) + 3 CaO(s) + 4 CuO(s) Tl2Ba2Ca3Cu4O12(s)
Tl2O3(l) + 2 BaO(s) + 3 CaO(s) + 4 CuO(s) -----> Tl2Ba2Ca3Cu4O12(s)
From the balanced equation:
3 moles of CaO requires -----> 2 moles of BaO
moles of CaO = mass/molarmass ( CaO = 56 g/mol)
= 5.0/56
= 0.0893 moles
3 moles of CaO requires -----> 2 moles of BaO
0.0893 moles of CaO requires ----> (2*0.0893)/3
= 0.0595 moles of BaO
moles of BaO needed = 0.0595 moles
In research on the synthesis of superconductors, the following reaction is studied. What amount (in moles) of BaO is nee...
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