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for 12. Using the reaction enthalpy data shown, determine the amount of heat released in each situation: 2 Ca(s) + O2(g) → 2
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Answer #1

12)

a)

From reaction,

When 1 mol of O2 reacts, ΔH = -1269.8 KJ

So, for 3 moles of O2, ΔH = -3*1269.8 KJ = -3809.4 KJ

Answer: -3809.4 KJ

b)

From reaction,

When 2 mol of Ca reacts, ΔH = -1269.8 KJ

So, for 8 moles of Ca, ΔH = -8*1269.8/4 KJ = -2539.6 KJ

Answer: -2539.6 KJ

c)

From reaction,

When 2 mol of CaO forms, ΔH = -1269.8 KJ

So, for 1 moles of CaO, ΔH = -1269.8/2 KJ = -634.9 KJ

Answer: -634.9 KJ

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