Question

all please. its okah if its just the answers

ozmol 53. A 100.0 mL sample of 0.20 M HF is titrated with 0.10 M KOH. Determine the pH of the solution after the addition of 400.0 mL of KOH. The Ka of HF is 3.5 x 10-4. a.)12.30 b. 12.60 с. 12.78 d. 13.85 HI & KOH + H₂O .04 54. Which response has both answers correct? Will a precipitate form when 250 mL of 0.33 M Na CO. are added to 250 mL of 0.12 M AgNO:? [K(AgaCros) = 1.1 x 10-2). What is the concentration of the silver ion remaining in solution? a. Yes, [Ag'1 -2.9 x 10M. b. Yes, [Ag'] = 0.060 M. c. Yes, [Ag'] = 1.3 x 10-4M. d. No, [Ag'] = 0.060 M. 95. What volume of 0.200 M potassium hydroxide should be added to 300. mL of 0.150 M propanoic acid (CH3COOH) to obtain a solution with a pH of 5.25? [K (C2H5COOH) = 1.34 x 10 a. 32 mL b. 210 ml 160 mL d. 13 mL (150) 6300) = 1.200 ) (ml 28mb = V.

Answer 1

HF 0.20M - KF t tho t koy 0,10m 4oom! 100ml 20 mmol 40 mmol 20 mmol 20mmol ph will be due to kon only 20 [kon] = 500 Cori] = 4x10-2 pont a toy loni] = -loy Lyx102) = 2-1094 -2-2log 2 = 2 .0.6 pon = 1.4 pH = 14-1.4 = 12.6 Ans (54) Macroy 250m1, 0.3314 & AgNO3 250ml, 0.12 M Come of croy?- in mixture [cro, 2-) = 250 x0,33. 500 - 0.165 M

250 X 0.12 0.06 M Ag croy = 2 Ag+ + croyl- 9sp = lngty? [ coop = (0,06120.165) = 5.94x104 precipitation will form * lsp (yes) KLR 2 Agtar + crop lag 2 Ag, Croy (s) 0.165 o so o 0,165-0.00 0,135 Ksp = 1 Agt 2 [ crop ?) anal 1.1x10-12 = y2 x 0.135 y = 2-85x10-6 ? 3.9 X10 CM Yes (Agth = 2.9 X 10 M

KoH + Cooи = 4 cook 0, 20 м N mi 0.15M 30 m2 о. - у 45 mmol ИТ-о. 2v 6.2 V P1 = p + Г С сам, со ѕt ) [C, и оси) 5, 2s 2 ч. 873 + |оо. 2 Чs-oy 0.311 0.2y Чs — ору 2. 38 - о. 2 у Чr– 0,2V lo7. 1 – о, чт 6 - о, у о. 676 y = 107) т. уз ~ ~ 160ml