Question

Answer the questions for the following reaction: NaOCH, methanol Accounting for any functional groups, the reactant is classi

options:

1 & 2: alcohol, cycloalkyne, alkyl halide, alkene.

3: addition, substitution, elimination, condensation.

4: Na, H, O, C, none
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Answer #1

As we can see our reactant is Chlorocyclopentane which is nothing but haloalkane or we can say alkyl halide both are correct. The functanility came because chlorine is halogen. So haloalkane or alkyl halide isfunctional group.

Now product has one double bond so it comes under alkene functionality.

Type of reaction is elimination reaction. Because in elimination reaction two substituents are removed from one molecule.

Apart from Cl hydrogen molecule lost from reactant molecule to get alkene as product of elimination reaction.

Go through attached image to get clear understanding.

Methanol

So the above statement can be written as follows,

According for any functional groups the reactant is classified as alkyl halide and the product is a type of alkene. The reaction that occurred is called elimination reaction. Apart from chlorine other has lost is hydrogen.

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