2 NaN3 = 2 Na + 3 N2
Moles of NaN3 = mass / molar mass
= 10.5 / 65
= 0.16154
Moles of N2 = 3/2 moles of NaN3
= 3/2 * 0.16154
= 0.24231
Pressure = 726 torr = 0.9553
Temperature = 112°C = 385.15 K
Volume = moles * gas constant * temperature / pressure
= 0.24231 * 0.082 * 385.15 / 0.9553
= 8.011 Litres
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