2. a) Balance the equation below and use it to calculate the moles of Fe formed from \(0.50\) moles of \(\mathrm{Fe}_{2} \mathrm{O}_{3}:\)
$$ \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s})+\mathrm{CO}(\mathrm{g}) \stackrel{\Delta}{\rightarrow} \mathrm{Fe}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) $$
3. Balance the equation below then calculate the mass of \(\mathrm{ZnCl}_{2}\) by obtained by reacting \(10.0 \mathrm{~g}\) of zinc metal with an excess (more than is required) of hydrochloric acid
$$ \mathrm{Zn}(\mathrm{s})+\mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{ZnCl}_{2}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g}) $$
2. a) Balance the equation below and use it to calculate the moles of Fe formed from 0.50 moles of Fe,O3: Fe2O3(...
Zinc will react with hydrochloric acid to give hydrogen in accord with the equation given below. How many mL of a 3M solution HCL are required to react with 10.0 g of zinc? ( Molar mass of Zn=(65.41 g/mol ) Zn(s) + 2 HCL(aq) ====>ZnCl2(aq) + H2 (g)
Zinc metal reacts with hydrochloric acid (HCI) according to the equation: Zn(s) + 2HCl(aq) - ZnCl(aq) + H2(g) Part A How many grams of hydrogen are produced if 300 g of zinc reacts? AEP O ? M . Submit Request Answer
# Review Zinc metal reacts with hydrochloric acid according to the following balanced equation Zn(s) + 2HCI(M)-ZnCl(aq) + H ) When 0.116 g of Zn(s) is combined with enough HCl to make 51.5 mL of solution in a cottee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.5°C to 24.4°C Find A for this reaction as written (Use 1.0 g/ml. for the density of the solution and 4.18 J/8" as the specific heat capao 10...
Zinc metal reacts with hydrochloric acid according to the following balanced equation. Zn(s) + 2HCl(aq) -> ZnCl2(aq) + H2(g) When 0.104g of Zn(s) is combined with enough HCl to make 54.5 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.4 Celcius to 24.7Celcius. Find the delta Hrxn (in kJ/mol) for this reaction as written. (Use 1.0g/mL for the density of the solution and 4.18 J/g *Celcius as the specific...
Zinc metal reacts with hydrochloric acid according to the following balanced equation. Zn(s) + 2HCl(aq) --> ZnCl_2(aq) + H_2(g) When 0.124 g of Zn(s) is combined with enough HCl to make 51.3 mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 21.5 C to 23.9 C. Find Delta Hrxn for this reaction as written. (Use 1.0 g/mL for the density of the solution and 4.18 J/g *C as the specific...
determine how many grams of hydrogen gas are produced from 27.2 g of HCl 4. Zinc metal reacts with hydrochloric acid giving off hydrogen gas, H2 according to the equation: H2() ZnCl2 (aq) + Zn )+2HCI (n) Balance the equation b. Determine how many moles of zinc are required to produce 6.25 moles of hydrogen gas? Imol Zn Imol ta Le.25 mol tH Le 25 me Zn c. Determine how many grams of zinc are required to produce 4.5 moles...
23. How many molecules of \(\mathrm{HCl}\) are formed when \(80.0 \mathrm{~g}\) of water reacts according to the following balanced reaction? Assume excess ICl_3.$$ \mathrm{ICl}_{3}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+\mathrm{HCl} $$A) \(4.46 \times 10^{24}\) molecules \(\mathrm{HCl}\)B) \(2.68 \times 10^{24}\) molecules \(\mathrm{HCl}\)C) \(8.04 \times 1024\) molecules \(\mathrm{HCl}\).D) \(5.36 \times 10^{24}\) molecules \(\mathrm{HCl}\)E) \(4.46 \times 1025\) molecules \(\mathrm{HCl}\)24. Determine the oxidation state of \(\mathrm{P}\) in \(\mathrm{PO}_{3}^{3-}\)A) \(+3\)B) \(+6\)C) \(+2\)D) 0E) - 325. Give the complete ionic equation for the reaction (if any) that occurs when...
Gas Laws Pre-Lab Name Section 1. Calculate the number of moles of hydrogen gas generated when 0.214 g of zinc reacts with hydrochloric acid Zn(s) + 2HCl(aq) --ZnCl (aq) +Hy(@) 2. Calculate the number of moles of hydrogen gas generated if the cudiometer volume is 76.34 mL, the total pressure of H, generated over water is measured to be 755.0 torr, and the temperature is 22.0°C. P o ar 22.0°C = 19.8 torr) (R = 62.36 L torr/mol K or...
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s) + 2 HCl(aq) — ZnCl2 (aq) + H (9) How many milliliters of 5.00 M HCl(aq) are required to react with 3.05 g Zn(s)? volume:
Calculate the volume of hydrogen produced at 2.50 atm and 22°C by the reaction of 25.4 g of zinc with excess hydrochloric acid according the balanced chemical equation below. Zn (s) + 2 HCl (aq) ® ZnCl2 (aq) + H2 (g)