Question

# Review Zinc metal reacts with hydrochloric acid according to the following balanced equation Zn(s) + 2HCI(M)-ZnCl(aq) + H ) When 0.116 g of Zn(s) is combined with enough HCl to make 51.5 mL of solution in a cottee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 22.5°C to 24.4°C Find A for this reaction as written (Use 1.0 g/ml. for the density of the solution and 4.18 J/8" as the specific heat capao 10 AERO? kJ/mol Submit Request Answer Provide Feedback

Answer 1

Mass of solution = volume * density

= 51.5 * 1.0

= 51.5 grams

Q = mass * specific heat * ∆T

= 51.5 * 4.184 * ( 24.4 - 22.5 )

= 409.4 J

Moles of Zn = mass / molar mass

= 0.116 / 65.38

= 1.77*10^-3

1.77*10^-3 moles of zinc release = 409.4 J

1 moles will release = (409.4)/(1.77*10^-3)

= 230746.31 J/mol

Or 230.746 KJ/mol

Or -230.746 KJ/mol ( heat is released )

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