Question

Cu(OH)2 can be obtained from the addition of excess NaOH solution to a solution of Cu(NO3)2 as shown in the figure. If the NaOH is added to 35.0 mL of 0.167 M Cu(NO3)2 and the precipitate isolated by filtration, what is the theoretical yield of Cu(OH)2? Cu(NO3)2 (aq) + 2 NaOH (aq) → Cu(OH)2 (s) + 2 NaNO3(aq) 0.4718 5858 1.10 g 0.570 g 1.14g

Answer 1

Answer 8- Page No -O Given , Cu (OH), can be obtained from the addition of excess Naoh solution to a solution of Cu(NO3)2 If the NaOH is added to 350 ml of 0.167 H Curios), and the precipitate isolated by filtration. Reaction : Ca CNO, ), Caaj) + 2NbOH 601) >culoh), (s) + 2 NANO, (09) Molarity 1 mo of Moles of solute - volume of solution in litres. 0.167 mol = No of moles of Cu(NO) - 350x103 L :. No. of Holes Of Cu Chos), = 0.167 rolle x SS-OXTO = 5.845 X10 Mol. i Mole CUCNO), yields I Hol of Culot): SO Do 5.845 x103 mol Cu(NO3), yields 5.845 x15 mol of Cu(он),

Mass of Cu Cot) produced 1 Page No o = 5.845x10 molx 97.56 g/mol = 570.23 x103 = 0.570 g I Theoretical yield = 0.570 g of Cu(OH) so the answer is, 0.570 g