how many moles of calcium carbonate will be produced from 4.21 mol of sodium carbonate?

Question

Question

For the chemical reaction

Na₂CO₃+Ca(NO₃)₂→CaCO₃+2NaNO₃

Answer 1

Answer #1

From the balanced equation we can say that

1 mole of Na2CO3 produces 1 mole of CaCO3 so

4.21 mole of Na2CO3 will produce

= 4.21 mole of Na2CO3 *(1 mole of CaCO3 / 1 mole of Na2CO3)

= 4.21 mole of CaCO3

mass of 1 mole of CaCO3 = 100.0869 g so

the mass of 4.21 mole of CaCO3 = 421 g

Therefore, the mass of CaCO3 produced would be 421 g

Answer 2

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