1. After a 6.387 g sample of impure SnCl4.2H2O (Mn=296.7 g/mol) was throughly heated, 5.690 g remained
b) How many grams of the hydrate were present in the sample?
c) What is the % m/m of the hydrate in the sample?
Homework Answers
Answer:-
Firstly from the given data, mass of water is calculated then from the calculated mass of water, mass of hydrate is calculated and percent is also calculated.
The answer is given in the image,
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1. After a 6.387 g sample of impure SnCl4.2H2O (Mn=296.7 g/mol) was throughly heated, 5.690 g remained b) How many g...
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Only part B is incorrect
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Please explain. Thank you.
(1) When a sample of ferric sulfate hydrate (EeSO4 XH20(s)) is heated to 270 C in an otherwise empty 625-mL container, it decomposes into ferric oxide (EeO(s), M 71.85 g/mol), sulfur trioxide (SO3(g), M = 80.06 g/mol), and water vapor (H20(g) 18.02 g/mol) wwwww = M = FESO4 XH2O(s) FeO(s) SO3(g) x H20 (g) wwwww www When all the FeSO4xH2O(s) in the sample decomposes, 1.80 g of FeO(s) forms and the total pressure of all gases...
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